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iogann1982 [59]
3 years ago
8

I have to get this done today 

Physics
1 answer:
cricket20 [7]3 years ago
3 0
It is simply a question of the amount of water contained, a lake is much bigger than a pool. The energy ratio is just the ratio of the masses of water concerned. <span>Thermal energy is the total kinetic energy of the particles in a substance .</span>The lake is larger, so it contains more total particles than the swimming pool. The thermal energy of a lake is greater than a swimming pool because the lake is larger.
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The layers of the atmosphere are divided into layers based on changes in __________.
Umnica [9.8K]
A. altitude should be correct
6 0
3 years ago
In which does sound travel fastest? Question 8 options: solids liquids gases plasma.
Kazeer [188]

Sound travels fastest in solids. A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.

<h3>What is sound?</h3>

A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.

It can propagate through a solid, a liquid, or a gas as its medium. Solids go the fastest, liquids are slower, and gases are the slowest.

Sound travels the quickest through a solid because the molecules are packed together densely, allowing sound waves to leap from one molecule to the next more quickly.

Because the molecules in solids are packed the tightest, sound travels the quickest through them, whereas sound travels the slowest through gases.

To learn more about the sound refer to the link;

brainly.com/question/927975

4 0
3 years ago
6. An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of t
zubka84 [21]

Answer:

The distance away the center of the earthquake is 1083.24 km.

Explanation:

Given that,

Speed of transverse wave = 9.1\ km/s

Speed of longitudinal wave = 5.7 km/s

Time = 71 sec

We need to calculate the distance of transverse wave

Using formula of distance

d=v\times t

d=9.1\times t....(I)

The distance of longitudinal wave

d=5.7\times (t+71)....(II)

From the first equation

t=\dfrac{d}{9.1}

Put the value of t in equation (II)

d =5.7\times(\dfrac{d}{9.1}+71)

\dfrac{9.1d-5.7d}{9.1}=71\times5.7

d0.3736=404.7

d =1083.24\ km

Hence, The distance away the center of the earthquake is 1083.24 km.

6 0
3 years ago
The greenhouse effect keeps earth warmer than it would normally be. True False
MariettaO [177]

Answer:

The World Is Pure Enough as it is that we don't melt or (lose air) \_/

Explanation:

All people don't have to be concerned about is a disruption of the plethora of gases we already have in our atmosphere and trees need C02 in order to breath and that's what cows produce that's what we breath out and what coal plants and fossil fuels produce the more C02 the more trees produce oxygen because trees breathe in C02 and pop out Oxygen and plus power plants don't produce C02 they produce water vapor so (ALL IN ALL C02 Will not cause the Ice Caps to melt because trees already have that issue covered that's why the scientists said they fixed the global warming issue to keep people from whining about a non-existent problem. so basically its true The greenhouse effect does keep the earth warm halfly because of the hot gases that get trapped in the atmosphere like C02.True

6 0
4 years ago
In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co
labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m

a)

The final velocity of cart 1 after collision is given as:

v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\  Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s

The final velocity of cart 2 after collision is given as:

v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\  Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s

b) Using the law of conservation of energy:

\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm

7 0
3 years ago
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