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Yuliya22 [10]
4 years ago
9

In _______ atomic model, negative electrons orbit the positively charged nucleus.

Physics
2 answers:
Shalnov [3]4 years ago
8 0
In (A. Dalton's) atomic model, negative electrons orbit the positively charged nucleus.
yarga [219]4 years ago
5 0

I think you are looking for B. That sounds very much like Rutherford's model of the atom.


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A kangaroo has a maximum gravitational potential energy during one jump of 770 J
KengaRu [80]

Answer:

k = 44000 N/m

Explanation:

Given the following data;

Maximum gravitational potential energy = 770 J

Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J

Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m

To find the spring constant, k;

The elastic potential energy of an object is given by the formula;

E.P.E = \frac {1}{2}kx^{2}

Substituting into the equation, we have;

107.8 = \frac {1}{2}*k*0.07^{2}

107.8 = \frac {1}{2}*k*0.0049

Cross-multiplying, we have;

215.6 = k*0.0049

k = \frac {215.6}{0.0049}

k = 44000 N/m

5 0
3 years ago
Is vectors and motion in plane same?
suter [353]

Answer:

<em>Plane Motion</em>

<em>Plane Motion One of the most common examples of motion in a plane is Projectile motion.</em>

8 0
2 years ago
The Cleveland City Cable Railway had a 14-foot-diameter pulley to drive the cable. In order to keep the cable cars moving at a l
dsp73

Answer:

13.94 rpm

Explanation:

Given that,

The diameter of the pulley, d = 14 foot

Radius, r = 7 foot

The linear velocity of the pulley, v = 14 mph = 20.53 ft/s

We need to find the angular velocity in rpm.

We know that, the relation between the linear velocity and the angular velocity is as follows :

v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{20.53}{14}\\\\\omega=1.46\ rad/s

or

\omega=13.94\ rpm

So, the angular velocity of the pulley is 13.94 rpm.

4 0
3 years ago
Physics Question please solve it​
andreyandreev [35.5K]
Solution:-

As we know that,

It is given that the resistance of two conductors in parallel is 12 ohm and in series is 50 Ohm.

Given,

r1 = 12 Ohm
r2 = 50 Ohm

Let r1 and r2 be the unknown resistance.

(i).

When the resistances are in series combination.

It is given that:

r1 + r2 = 50 Ohm.

(ii).

When the resistances are in parallel combination.

As we know that,

=>1/r1 + 1/r2

=> r1r2/r1 + r2 = 1/R(say)

where R is given as 12 Ohm.

Therefore, r1 + r2 = 50 Ohm

and r1r2/r1 + r2 = 12 Ohm.

=> r1r2 = 12 × 50

=> r1r2 = 600

Also,

=> ( r1 - r2 )^2 = ( r1 + r2 )^2 - 4r1r2

=> ( r1 - r2 )^2 = 2500 - 4 × 600

=> ( r1 - r2 )^2 = 100

=> ( r1 - r2 )^2 = (10)^2

=> r1 - r2 = 10

From (i) and (iii), 2r1 = 60

Therefore, r1 = 30 Ohm and r2 = 20 Ohm.
7 0
4 years ago
Read 2 more answers
. A point light source is kept in front of a convex
enot [183]

Answer:

80

Explanation:

all you do is 40+40 and it equals 80

3 0
3 years ago
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