Answer:
k = 44000 N/m
Explanation:
Given the following data;
Maximum gravitational potential energy = 770 J
Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J
Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m
To find the spring constant, k;
The elastic potential energy of an object is given by the formula;
Substituting into the equation, we have;
Cross-multiplying, we have;
k = 44000 N/m
Answer:
<em>Plane Motion</em>
<em>Plane Motion One of the most common examples of motion in a plane is Projectile motion.</em>
Answer:
13.94 rpm
Explanation:
Given that,
The diameter of the pulley, d = 14 foot
Radius, r = 7 foot
The linear velocity of the pulley, v = 14 mph = 20.53 ft/s
We need to find the angular velocity in rpm.
We know that, the relation between the linear velocity and the angular velocity is as follows :

or

So, the angular velocity of the pulley is 13.94 rpm.
Solution:-
As we know that,
It is given that the resistance of two conductors in parallel is 12 ohm and in series is 50 Ohm.
Given,
r1 = 12 Ohm
r2 = 50 Ohm
Let r1 and r2 be the unknown resistance.
(i).
When the resistances are in series combination.
It is given that:
r1 + r2 = 50 Ohm.
(ii).
When the resistances are in parallel combination.
As we know that,
=>1/r1 + 1/r2
=> r1r2/r1 + r2 = 1/R(say)
where R is given as 12 Ohm.
Therefore, r1 + r2 = 50 Ohm
and r1r2/r1 + r2 = 12 Ohm.
=> r1r2 = 12 × 50
=> r1r2 = 600
Also,
=> ( r1 - r2 )^2 = ( r1 + r2 )^2 - 4r1r2
=> ( r1 - r2 )^2 = 2500 - 4 × 600
=> ( r1 - r2 )^2 = 100
=> ( r1 - r2 )^2 = (10)^2
=> r1 - r2 = 10
From (i) and (iii), 2r1 = 60
Therefore, r1 = 30 Ohm and r2 = 20 Ohm.
Answer:
80
Explanation:
all you do is 40+40 and it equals 80