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g100num [7]
2 years ago
7

Part D

Physics
1 answer:
anygoal [31]2 years ago
5 0

Answer: I didn't see a difference because the large ball's vertical displacement and velocity are the same as the small one's.

Explanation:

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The inductive reactance of the circuit is exactly twice the resistance: XL=2R. Adjust the phasor that represents the voltage acr
SVETLANKA909090 [29]

Answer:

∅=63.43^{0}

Explanation:

z=impedance

x_{l}=2R

R=R

The resultant of the resistances in the circuit is called impedance

x_{l} is inductive reactance of the circuit

R is the resistance of the resistor

z=\sqrt{xl^{2}+R^2 }

z=\sqrt{2R^{2}+R^2 }

Z=\sqrt{5R^2}

Z=R\sqrt{5}ohms

tan∅=2R/R

tan∅=2

∅=Tan^-1(2)

∅=63.43^{0}

phase angle is ∅=63.43^{0}

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3 years ago
How would clearing a forest to plant corn affect an enviroment
Oksanka [162]
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3 years ago
which religious group did not expand their membership by great numbers during the Second Great Awakening
Dimas [21]

Answer:

The Catholics.

Explanation:

see answer.

4 0
2 years ago
How many dots belong in the electron dot diagram of a boron(B) atom
sergij07 [2.7K]
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6 0
3 years ago
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If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
lana [24]

Answer:

Explanation:

Given that,

Mass of star M(star) = 1.99×10^30kg

Gravitational constant G

G = 6.67×10^−11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W =mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g(star) = GM(star)/R²

g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²

g (star) = 8.49 × 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 × 8.49 × 10¹¹

W = 5.98 × 10¹³ N

The weight of the person on neutron star is 5.98 × 10¹³ N

5 0
3 years ago
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