Consider the addition of an electron to the following atoms from the third period. Rank the atoms in order from the most negativ
e to the least negative electron affinity values based on their electron configurations. Note: 1 = most negative electron affinity ; 3 = least negative electron affinity
1 answer:
The question is incomplete, the atoms in the third period referred to in the question are shown in the image attached.
Answer:
Cl>Si>Ar
Explanation:
Electron affinity refers to the energy released when an atom accepts electron (s) to form a negative ion. It is a periodic property that shows similar trends as electro negativity.
Considering the atoms in period three given in the question; chlorine will have the most negative value of electron affinity. This owes to the fact that halogens accept electrons easily to form negative ions. Silicon in group 14 shows much less negative value of electron affinity while argon, a noble gas, does not accept electrons at all and has an electron affinity of zero KJMol-1 by standard.
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Answer:
at the beginning:
when the plates are pulled apart:
Explanation:
The capacitance of a parallel-plate capacitor is given by
where
k is the relative permittivity of the medium (for air, k=1, so we can omit it)
is the permittivity of free space
A is the area of the plates of the capacitor
d is the separation between the plates
In this problem, we have:
is the area of the plates
is the separation between the plates at the beginning
Substituting into the formula, we find
Later, the plates are pulled apart to , so the capacitance becomes