Question

A syringe contains 0.65 moles of he gas that occupy 900.0 ml. what volume (in l) of gas will the syringe hold if 0.35 moles of ne is added?

Answer 1

From the explanation, we are given that:

• The mole of gas n1 = 0.65 mol
• The volume it occupied V1 = 900.0 ml
• Mole of Neon = 0.35 ml

Further Explanation

To solve this question, we have to consider the Avogadro’s law, which state that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules”

Therefore, we have to calculate the total number of moles of the gases.

$(0.65 + 0.35) mol$

$1.00 mol$

Also we know that the volume it occupied V2 = unknown

According to the Avogadro’s law, the equation will be

$0.65 mol$ x $900.0ml$ = $1.00ml$ x $V2$

$585ml$ = $1.00 ml$ x $v2$

$V2$ = $585ml$

To convert 585ml to litre, then we have to divide the derived value by 1000

Therefore we have

$\frac{ 585ml}{1000}$

0.6L

Therefore, the volume of gas in liters that syringe will hold if 0.35 moles of neon is added is 0.6L

LEARN MORE:

• A syringe contains 0.65 moles of he gas that occupy 900.0 ml. what volume (in l) of gas will the syringe hold if 0.35 moles of ne is added?  brainly.com/question/6860167
• A syringe contains 0.65 moles of he gas that occupy 750.0 ml. brainly.com/question/6442444

KEYWORDS:

• moles
• syringe
• convert
• litres
• avogradro's law

Answer 2

PV=nRT= a universal constant For any condition P1V1/n1T1=R and P2V2/n2T2=R i.e P1V1/n1T1=P2V2/n2T2 Becomes V1/n1=V2/n2 rearranging and solving V2=V1X(n2/n1)= 750 mLx((0.65+0.35)/(0.65))=1200ml=1.2L...2 sig figs