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Oksana_A [137]
2 years ago
12

In the past earths sea level has sometimes been lower at that time which of the following would have been a major difference in

the ocean basins
Chemistry
2 answers:
valina [46]2 years ago
8 0
The answer which would have been a major difference in the ocean basins is the following one:
<span>B. Mid-ocean ridges would have been chains of mountains.

Given that the waters were lower in the past, those ridges would no longer be just mid-ocean ridges, but complete mountains due to the low levels of water around them.</span>
sdas [7]2 years ago
8 0

Answer:

The answer is mid-ocean rid would have been chains of mountains hopefully this helps!

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Even though the same amount of energy was transferred into both substances from the air, the isopropanol evaporated while the wa
Nesterboy [21]

Answer:

The isopropanol evaporated while the water did not because the molecules don't stick together as strongly as the molecules in the water do. The water would need more energy transferred in, in order to evaporate.

Explanation:

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3 years ago
Strontium phosphate, Sr3(PO4)2, is a crystalline substance used in medicine and industry. How many phosphorus atoms are represen
dexar [7]

Answer: option A. 2

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The amount of water that evaporates from earth is
astraxan [27]
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3 years ago
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How would you prepare 2.5 L of a 0.800M solution of KNO3?
statuscvo [17]
First  find the mass of <span>solute:

Molar mass KNO</span>₃ = <span>101.1032 g/mol

mass =  Molarity * molar mass * volume

mass = 0.800 * 101.1032 * 2.5

mass = 202.2064 g of KNO</span>₃

<span>To prepare 2.5 L (0800 M) of KNO3 solution, must weigh 202.2064 g of salt, dissolve in a Beker, transfer with the help of a funnel of transfer to a volumetric flask, complete with water up to the mark, capping the balloon and finally shake the solution to mix.</span>

hope this helps!
7 0
3 years ago
In the reaction 2Mg (s) + O2 (g) + 2H2O (l) → 2Mg2+ (aq) + 4OH– (aq), which substance is reduced?
Bogdan [553]

F. <em>None of the above </em>

<em>No O atoms are present</em> as reacting substances, only O_2 and H_2O molecules.

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We must use <em>oxidation numbers</em> to decide whether oxygen or water is the substance reduced.

The oxidation number of O changes from 0 in O_2 to -2 in OH^(-).

A decrease in oxidation number is <em>reduction</em>, so O_2 is the substance  reduced.

The oxidation number of O is -2 in both H_2O and OH^(-), so water is <em>neither oxidized nor reduced</em>.

6 0
3 years ago
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