Hi there!
<u>Set A has a LARGER standard deviation. </u>
A set's standard deviation is equivalent to:
![\sigma = \frac{\sqrt{\Sigma (x - \mu)^2 }}{n-1}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B%5Csqrt%7B%5CSigma%20%28x%20-%20%5Cmu%29%5E2%20%7D%7D%7Bn-1%7D)
σ = standard deviation
x = value
μ = mean
n = # of observations
Basically, standard deviation is calculated using how far apart EACH value is from the set's mean. If more values are FARTHER away from the mean, the standard deviation increases and vice-versa.
Set A has a GREATER RANGE and its values are farther from 13 on both sides compared to Set B which has a SMALLER RANGE and its values are closer to 13.
Therefore, Set A will have a larger standard deviation.
Equation A:= True and has an infinite number of solution and B: is False no solution exists thus d: is your Answer.
Answer:
A.) Even.
Step-by-step explanation:
If a function is an even function, then
F(-x) = f(x)
Also, if a function is an odd function, then, f(-x) = -f(x)
You are given the below function
f(x) = 1 + 3x^2 − x^4
Let x = 2
Substitute 2 for x in the function
F(x) = 1 + 3(2)^2 - (2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Also, Substitute -2 for x in the function
F(x) = 1 + 3(-2)^2 - (-2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Since f(-x) = f(x), we can conclude that
F(x) = 1 + 3x^2 - x^4 is even
Answer:
I’m not sure but it think its 36
Step-by-step explanation:
10)So plug in the value of a + 3 into where the x of the equation
r(a+3)= 6 6 *you can simply if you want*
------- ______
(a+3)8 distribute=24 + 8a
11) f(-2)=n whenever you have f with a # inside the parenthesis know that they're giving you the x value so f(x)= and on this side is the y value but on tables y value are titled as f(x). So f(-2) is 3
12)Instead of giving you the x-value they gave you the y value this time "=9?" on the bottom. So you go to the f(x) column and find 9 and the # next to it which is 0