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Hatshy [7]
3 years ago
8

What is the difference between h+ concentration in an acidic solution such as lemon juice (ph 2) and a basic solution such as ho

usehold bleach (ph 13)?
Chemistry
1 answer:
katovenus [111]3 years ago
7 0

The pH of solution is calculated using the formula:

pH = - log [H]

where [H] is the concentration of H+ ion in molarity

 

H+ concentration when pH = 2:

2 = - log [H]

[H] = 0.01 M

 

H+ concentration when pH = 13:

13 = - log [H]

[H] = 1 x 10^-13 M

 

The difference is therefore:

0.01 M - 1 x 10^-13 M = 0.01 M

 

The concentration at pH=13 is so small that it can be considered negligible.

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Which of the following statements about chemical formulas is FALSE?A) The subscripts represent the relative number each type of
GuDViN [60]

Answer:

And=B

Explanation:

The subscripts does represent the relative mass of each type of atom in the compound, it represents relative number of atoms

5 0
3 years ago
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What statement is true about endothermic and exothermice reactions
Nat2105 [25]

Explanation:

exothermic reactions release energy, endithermic reactiond absorbs energy as usage

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4 years ago
What is the number if moles of nitrogen gas which react with 18 g of magnesium to form magnesium nitride compound?(mg=24,N=14)
makvit [3.9K]

Answer:

It is true. a) 0.25 mol

Explanation:

<em>Hello </em><em>there?</em>

To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.

The chemical equation is;

3Mg(s) + N2(g) => Mg3N2(s)

1 mole of Mg = 24g

We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)

From our equation,

Mole ratio = 3 : 1, (Mg : N2)

1 mol Mg = 24g

x mol Mg = 18g

x mol Mg = (18/24) = 0.75 mol Mg

But mole ratio = 3 : 1 (Mg : N2)

This means that 3 => 0.75 mol Mg

What about ratio 1 of N2?

N2 = (0.75 mol ÷ 3)/1

= 0.25 mol N2

<em>I </em><em>hope</em><em> </em><em>this </em><em>helps</em><em> </em><em>you </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Ha</em><em>v</em><em>e </em><em>a </em><em>nice </em><em>studies.</em><em> </em><em />

6 0
3 years ago
The IUPAC rules permit the use of common names for a number of familiar phenols and aryl ethers. These common names are listed h
fgiga [73]

Explanation:

a. Vanillin(4-hydroxy-3-methoxybenzaldehyde):

In its structure hydroxl group will be present on para position of the benzaldehyde ring and methoxy group on meta position.

b. Thymol (2-isopropyl-5-methylphenol):

In its structure isopropyl group will be present on ortho position of the phenol ring and methyl group on meta position.

c. Carvacrol (5-isopropyl-2-methylphenol):

In its structure isopropyl group will be present opposite to methyl group which is present ortho position in a phenol ring.

d. Eugenol (4-allyl-2-methoxyphenol):.

In its structure allyl group will be present on para position of the phenol ring and methoxy group on ortho position.

e. Gallic acid (3,4,5-trihydroxybenzoic acid):

In its structure hydroxyl group will be present on both meta positions and on para position of the benzoic acid ring.

f. Salicyl alcohol (o-hydroxybenzyl alcohol):

In its structure, -CH_2OH group is linkedto benzene ring and in respect to that hydroxyl group is present at ortho position of the ring.

6 0
3 years ago
The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
Pachacha [2.7K]

Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

n=\frac{90.09}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

7 0
4 years ago
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