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3 years ago

I really need help with this to be able to pass this last semester this is about (Circular Motion ) on physics

Physics

2 answers:

ankoles [38]3 years ago

4 0

Question 1
To find centripetal acceleration, use the formula : centripetal acceleration = v^2/r
so answer would be (3.71)^2/42.85=0.32 (2d.p.)
Question 2
Force =ma
a= (9.98)^2/31.77=3.1350
Force= 3.1350 * 56.63 = 177.54 (2 d.p.)

Aleonysh [2.5K]3 years ago

4 0

1) a=(v^2)/r
a=((3.71)^2)/42.85
a=0.32 m/s^2
2) F=m*(v^2)/r
F=56.63*(9.98^2)/31.77
F=177.54N

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2 years ago

Water flows without friction vertically downward through a pipe and enters a section where the cross sectional area is larger. T

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Answer:

$v_{2}$ will be less than $v_{1}$ and $P_{2}$ will be greater than $P_{1}$ .

Explanation:

As we know from the conservation of mass, the rate at which any amount of fluid mass ( $m_{1}$ ) is entering in a system is equal to the rate at which the same amount of fluid mass ( $m_{2}$ ) is leaving the system.

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$m = \rho A v$

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Now, according to the problem, as the density of the fluid does not change, we can write

$&& m_{1} = m_{2}\\&or,& \rho A_{1} v_{1} = \rho A_{2} v_{2}\\&or,& \dfrac{v_{2}}{v_{1}} = \dfrac{A_{1}}{A_{2}}$

where $A_{1}$ and $A_{2}$ are the cross-sectional areas through which the fluid is passing and $v_{1}$ and $v_{2}$ are the velocities of the fluid through the respective cross-sectional areas.

As according to the problem, $A_{2} > A_{1}$ , so from the above formula $v_{2} < v_{1}$ .

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3 years ago

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kherson [118]

Answer:

Yes

Explanation:

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3 years ago

Read 2 more answers

i)Distinguish between different methods of charging. ii) You are provided with a positively charged gold leaf electroscope. Stat

AleksAgata [21]

Answer:

Explanation:

On rubbing a glass rod with silk, the electrons from the glass rod get transferred to the silk. The silk now has an excess of electrons and so is negatively-charged. On the other hand, the glass rod is deficient in electrons and hence is positively-charged.

In the above case, the silk undergoes negative electrification.

Now, when the positively charged glass rod is touched on the disc of a negatively charged gold leaf electroscope, the electrons shifts towards rod, hence amount of charge on gold leaves decreases and the divergence between the gold leaves decreases as unlike charges attract each other.

Hence, the divergence decreases when a glass rod rubbed with silk is brought near the disc of negatively charged electroscope.

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2 years ago

A machine is supplied energy at a rate of 4,000 W and does useful work at a rate of 3,760 W. What is the efficiency of the machi

Dmitry_Shevchenko [17]

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3 years ago