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Marta_Voda [28]
3 years ago
14

I really need help with this to be able to pass this last semester this is about (Circular Motion ) on physics

Physics
2 answers:
ankoles [38]3 years ago
4 0
Question 1
To find centripetal acceleration, use the formula : centripetal acceleration = v^2/r
so answer would be (3.71)^2/42.85=0.32 (2d.p.)
Question 2
Force =ma
a= (9.98)^2/31.77=3.1350
Force= 3.1350 * 56.63 = 177.54 (2 d.p.)
Aleonysh [2.5K]3 years ago
4 0
1) a=(v^2)/r
a=((3.71)^2)/42.85
a=0.32 m/s^2
2) F=m*(v^2)/r
F=56.63*(9.98^2)/31.77
F=177.54N
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Two vectors have magnitudes of 10 and 15. The angle between them when they are drawn with their tails at the same point is 65. T
IrinaK [193]

Two vectors have magnitudes of 10 and 15. The angle between them when they are drawn with their tails at the same point is 65. The component of the longer vector along the line of the shorter is 6.33 .

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

The taller component will be 15 . There will be two components taller component , one in the direction of shorter component and other perpendicular to the shorter wavelength .

The component of longer wavelength in the direction of shorter will be  

= 15 cos (theta ) = 15 cos (65) = 6.33

where theta  is the angle between both the vectors

To learn more about vectors here

brainly.com/question/13322477

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2 years ago
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3 years ago
A multimeter in an RL circuit records an rms current of 0.600 A and a 50.0-Hz rms generator voltage of 110 V. A wattmeter shows
jeka57 [31]

Answer:

(a) The impedance in the circuit is Z=183.33\Omega.

(b)The resistance is R=38.89\Omega.

(c) The inuctance is 0.57 H.

Explanation:

(a)

The expression for the impedance is as follows:

Z=\frac{V_rms}{I_rms}

Here, V_rms is the rms voltage and I_rms is the rms current.

PutV_rms=110 V and I_rms=0.600 A.

Z=\frac{110}{0.600}

Z=183.33\Omega

Therefore, the impedance in the circuit is Z=183.33\Omega.

(b)

The expression for the average power is as follows;

P_{a}=I_{rms}^{2}R

Here, P_{a} is the average power and R is the resistance.

Calculate the resistance by rearranging the above expression.

R=\frac{P_{a}}{I_{rms}^{2}}

Put P_{a}=14W and

R=\frac{14}{{0.600}^{2}}

R=38.89\Omega

Therefore, the resistance is R=38.89\Omega.

(c)

The expression for the impedance is as follows;

Z^{2}=R^{2}+X_{L}^{2}

Here,X_{L} is the inductive reactance.

Put Z=183.33\Omega and R=38.89\Omega.

(183.33)^{2}=(38.89)^{2}+X_{L}^{2}

X_{L}=179.16\Omega

The expression for the inductive reactance in terms of  frequency is as follows;

X_{L}=2\pi fL

Here, L is the inductance.

Calculate the inductance by rearranging the above expression.

L=\frac{X_{L}}{2\pi f}

Put X_{L}=179.16\Omega and f=50Hz.

L=\frac{179.16}{2\pi (50)}

L=0.57 H

Therefore, the inuctance is 0.57 H.

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3 years ago
Name the four forces in physics?​
avanturin [10]

Answer:

Gravitational

Electrostatic

magnetic

Frictional

7 0
3 years ago
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