All categories

4 years ago

A. If an electron in a hydrogen atom has an energy of −6.06 × 10^−20 J, which Bohr orbit is it in?

Physics

1 answer:

Orlov [11]4 years ago

3 0

Explanation:

yea because cheese and jdouchvehdjdjdbsjjs d d d d d d d d d d djxjxjx s djxbsbs zjxh d d d

You might be interested in

If there is no gravity what will happen to earth?

Serga [27]

Wouldn't everything fall?

7 0

3 years ago

Read 2 more answers

What are the five advantages of using machine and tools in our daily life?

daser333 [38]

Answer:

it makes our work easy and

time saving

it multiply our force applied

it complete our work with high efficiency

by using this,less effort is required for the work.

7 0

3 years ago

What are the equations of angular acceleration, angular velocity and theta?.

soldier1979 [14.2K]

Θ is the angular displacement = ωt
ω is the angular velocity = θ/t
α is the angular acceleration = ω/t

3 0

3 years ago

Which of these planets is the odd one out based on their physical features?

Maurinko [17]

Answer:

mars

Explanation:

the planet that is the odd is Mars

7 0

3 years ago

A flutist assembles her flute in a room where the speed of sound is 342 m/s. When she plays the note A, it is in perfect tune wi

sertanlavr [38]

Answer:

5.15348 Beats/s

4.55 mm

Explanation:

$v_1$ = Velocity of sound = 342 m/s

$v_2$ = Velocity of sound = 346 m/s

$f_1$ = First frequency = 440 Hz

Frequency is given by

$f_2=\frac{v_2}{2L_1}\\\Rightarrow f_2=\frac{346}{2\times 0.38863}\\\Rightarrow f_2=445.15348\ Hz$

Beat frequency is given by

$|f_1-f_2|=|440-445.15348|=5.15348\ Beats/s$

Beat frequency is 5.15348 Hz

Wavelength is given by

$\lambda_1=\frac{v_1}{f}\\\Rightarrow \lambda_1=\frac{342}{440}\\\Rightarrow \lambda_1=0.77727\ m$

Relation between length of the flute and wavelength is

$\lambda_1=2L_1\\\Rightarrow L_1=\frac{\lambda_1}{2}\\\Rightarrow L_1=\frac{0.77727}{2}\\\Rightarrow L_1=0.38863\ m$

At v = 346 m/s

$\lambda_2=\frac{v_2}{f}\\\Rightarrow \lambda_2=\frac{346}{440}\\\Rightarrow \lambda_1=0.78636\ m$

$L_2=\frac{\lambda_2}{2}\\\Rightarrow L_2=\frac{0.78636}{2}\\\Rightarrow L_2=0.39318\ m$

Difference in length is

$\Delta L=L_2-L_1\\\Rightarrow \Delta L=0.39318-0.38863\\\Rightarrow \Delta L=0.00455\ m=4.55\ mm$

It extends to 4.55 mm

7 0

3 years ago