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3 years ago

Need answers quick !! will give brainliest !!

Physics

1 answer:

stiv31 [10]3 years ago

6 0

Answer:

use the bowl of water because Earth's magnetic field is relatively weak. Allowing it to float freely on the water, allows the magnetized needle to freely react to Earth's magnetic field, causing it to align North to South. If you watched closely, the same end of the needle should always point to the North

Explanation:

You might be interested in

Gases and particles which are put into the air or emitted by various sources are called __________. photochemical smog emissions

Doss [256]

The correct answer is "emissions".

5 0

4 years ago

Read 2 more answers

A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic

Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light $c= 2.99793\times10^{8}\ m/s$

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

$\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}$

Put the value into the formula

$\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}$

$\Delta l=1\sqrt{1-(0.96)^2}$

$\Delta l=0.28\ m$

We need to calculate the time the stick take to move

Using formula of time

$t=\dfrac{\Delta l}{v}$

Put the value into the formula

$t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}$

$t=9.72\times10^{-10}\ sec$

$t=0.97\ ns$

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0

3 years ago

suppose 1 gold bar is 6 cm long, 2 cm high, and 3 cm wide. how many whole gold bars will you be able to fit in a vault with a vo

Gemiola [76]

To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values,
v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.

5 0

3 years ago

Two capacitors, C1 and C2, give an equivalent capacitance of 9.0 pF when connected in parallel and an equivalent capacitance of

Lilit [14]

Answer:

C₁ = 3 pF

C₂ = 6 pF

Explanation:

Let the capacitance be C₁ and C₂.

For parallel combination

C₁ +C₂ = 9

For series combination

$2=\frac{C_1\times C_2}{C_1+C_2}$

$2=\frac{C_1\times C_2}{9}$

C₁ X C₂ = 18

( 9-C₂ )X C₂ = 18

C₂²- 9C₂ +18 = 0

C₂ = 6 or 3.

C₁ = 3 or 6.

C₁ = 3 pF

C₂ = 6 pF

5 0

3 years ago

Find the components to write this vector in unit vector notation: 63.5 A please help

IrinaVladis [17]

Vector is perpendicular to x axis or i component.

Hence i component is 0

j component is 63.5

$\\ \sf\longmapsto \overrightharpoon{A}=0\hat{i} +63.5\hat{j}$

6 0

3 years ago