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3 years ago

11

According to the kinetic theory, all matter is composed of _______.

2 answers:

drek231 [11]3 years ago

5 0

Answer:

According to the kinetic theory, all matter is composed of _______.

Explanation:

The Kinetic Theory of Matter states that matter is composed of a large number of small particles, individual atoms or molecules, that are in constant motion. Matter is made up of particles that are constantly moving. All particles have energy, but the energy depending on the temperature of which matter is in.

9966 [12]3 years ago

3 0

Answer:

the kinetic theory of matter stated that all matter is made of small particles that are in a random motion and that have space between them. this means that no matter what phase matter is in, it is made of separate, moving particles.

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3 years ago

A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the a

finlep [7]

Solution :

Let $m_1=m_2=4$ kg

$u_1 = 5$ m/s

Let $v_1$ and $v_2$ are the speeds of the disk $m_1$ and $m_2$ after the collision.

So applying conservation of momentum in the y-direction,

$0=m_1 .v_1_y -m_2 .v_2_y$

$v_1_y = v_2_y$

$v_1 . \sin 60=v_2. \sin 30$

$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$

$v_2=1.732 \times v_1$

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

$m_1.u_1=m_1.v_1_x+m_2.v_2_x$

$u_1=v_1_x+v_2_x$

$5=v_1. \cos 60 + v_2 . \cos 30$

$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$

$v_1 = 2.50$ m/s

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= 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

5 0

2 years ago

An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.50 mT. The angular momentu

liberstina [14]

Answer:

Explanation:

The angular momentum of electron mvR = 6 x 10⁻²⁵ Js

Magnetic field B = 2.5 x 10⁻³ T

radius of circular path R = mv / Bq

where m is mass , v is velocity and q is charge on electron

R² = mvR / Bq

R² = 6 x 10⁻²⁵ / 2.5 x 10⁻³ x 1.6 x 10⁻¹⁹

= 1.5 x 10⁻³

R = 3.87 x 10⁻² m

mvR = 6 x 10⁻²⁵

v = 6 x 10⁻²⁵ / mR

= 6 x 10⁻²⁵ / 9.1 x 10⁻³¹ x 3.87 x 10⁻²

= .17 x 10⁸

= 17 x 10⁶ m/s

6 0

3 years ago