Answer:
<h2><em>
34.46m</em></h2>
Explanation:
Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;
v is the final velocity of the bicyclist = 26m/s
u is the initial velocity of the bicyclist = 0m/s
a is the acceleration due to gravity = 9.81m/s
s is the distance covered during travel
Substitute the given parameters into the formula above to get the distance traveled
26² = 0² + 2(9.81)s
676 = 19.62s
Divide both sides by 19.62
676/19.62 = 19.62s/19.62
s = 34.46m
<em>The distance traveled by the bicyclist during the race is 34.46m</em>
Answer:
Approximately
, assuming that
.
Explanation:
Let
and
denote the mass and acceleration of Spiderman, respectively.
There are two forces on Spiderman:
- Downward gravitational attraction from the earth:
. - Upward tension force from the strand of web
.
The directions of these two forces are exactly opposite of one another. Besides, because Spiderman is accelerating upwards, the magnitude of
(which points upwards) should be greater than that of
(which points downwards towards the ground.)
Subtract the smaller force from the larger one to find the net force on Spiderman:
.
On the other hand, apply Newton's Second Law of motion to find the value of the net force on Spiderman:
.
Combine these two equations to get:
.
Therefore:
.
By Newton's Third Law of motion, Spiderman would exert a force of the same size on the strand of web. Hence, the size of the force in the strand of the web should be approximately
(downwards.)
I think the answer is potential