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Triss [41]
4 years ago
14

Why do city water departments first remove dissolved organic substances before disinfecting with chlorine?

Chemistry
2 answers:
alukav5142 [94]4 years ago
6 0
Dissolved organic substance present in natural water is a complex mixture compounds and contains most of the reduced carbon present in aquatic ecosytem . this can not be easily treated or disinfected by the conventional treatment . the experiments show that water sample with higher dissolved substance need higher cholrine demand  . this is the reason that before disinfecting with chlorine ..... need to remove organic substance {{{    because it increase chlorine demand }}}
lina2011 [118]4 years ago
3 0
<span><u><em>Answer:</em></u>
1- Because these organic substances increase the demand for chlorine
2- can cause cancer when combined with chlorine

<u><em>Explanation:</em></u>
<u>This is mainly due to two important reasons:</u>
1- The organic substances dissolved in water have very complex structure as they contain contain most of the reduced carbon found in the aquatic ecosystem and cannot be easily disinfected using the traditional methods.
These substances require <u>very large quantities of chlorine</u> in order to be disinfected and produce the desired results (this is proved by practical experiments).

2- When combined with large quantities of chlorine, <u>trihalomethanes</u> can be produced. This is a very dangerous product that causes cancer

Hope this helps :)</span>
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For IR radiation with û = 1,130 cm 1, v=__THz
Dmitry [639]

<u>Answer:</u> The frequency of the radiation is 33.9 THz

<u>Explanation:</u>

We are given:

Wave number of the radiation, \bar{\nu}=1130cm^{-1}

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

\bar{\nu}=\frac{1}{\lambda}

where,

\bar{\nu} = wave number = 1130cm^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, 8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m

  • The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of the radiation = ?

Putting values in above equation, we get:

\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}

\nu=0.339\times 10^{14}Hz

Converting this into tera Hertz, we use the conversion factor:

1THz=1\times 10^{12}Hz

So, 0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz

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7 0
3 years ago
2) What group of elements are most likely to react with<br><br> helium? Explain why.
Luba_88 [7]

Answer:

Helium does not react with any element

Please find the explanation below

Explanation:

Helium (He) is an element in group 8A of the periodic table, which is a group of element referred to as NOBLE GASES. Other elements in this group are Xenon (Xe), Krypton (Kr), Neon (Ne) etc.

One major characteristics of Helium and other Noble gases that makes them so UNREACTIVE is that they have a full electronic configuration i.e. they have a full electron shell and do not share electrons with any element, which is the basis of REACTING. For this reason, Helium will not react with any element.

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3 years ago
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g100num [7]

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8 0
3 years ago
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Mnenie [13.5K]

Answer:

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Explanation:

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