Answer:
Option A decreases with increase in altitude
Explanation:
This can be explained as the value of gravitational acceleration, 'g' is not same everywhere.
It has its maximum value at poles of the Earth and minimum on its equator.
Thus a person will weigh more at poles than equator.
This variation is in accordance to:
Thus the gravitational acceleration changes as inverse square of the Radius of the Earth.
Thus as we move away from the Earth's center, gravitational acceleration, g decreases.
Answer:
Vy = 80.5 [m/s]
Explanation:
In order to solve this problem we must use the Pythagorean theorem.
V = 90 [m/s]
The components are Vx and Vy:
Therefore:
where:
Vy = 2*Vx ; because one is twice of the other.
![90 = \sqrt{v_{x}^{2} +(2*v_{x})^{2} }\\ 90 =\sqrt{v_{x}^{2}+4*v_{x}^{2}} \\90 =\sqrt{5v_{x}^{2}} \\90=2.23*v_{x} \\v_{x}=40.25[m/s]](https://tex.z-dn.net/?f=90%20%3D%20%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%20%20%2B%282%2Av_%7Bx%7D%29%5E%7B2%7D%20%7D%5C%5C%2090%20%3D%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%2B4%2Av_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%20%3D%5Csqrt%7B5v_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%3D2.23%2Av_%7Bx%7D%20%5C%5Cv_%7Bx%7D%3D40.25%5Bm%2Fs%5D)
and the bigger vector is:
Vy = 40.25*2
Vy = 80.5 [m/s]
(A) A device that converts heat into work with 100% efficiency
It clearly violates the second law of thermodynamics because it warns that while all work can be turned into heat, not all heat can be turned into work. Therefore, despite the innumerable efforts, the efficiencies of the bodies have only been able to reach 60% at present.
For any pure substance, the boiling point and melting point will always remain sharp or distinct. This is because the substance has uniform properties all throughout. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
A stone on the ground does not have zero energy…there is an internal potential in every object. Aldo is not in action or in any mechanical motion it is being acted upon by gravity and also molecular forces and energy.
<em>Hope</em><em> </em><em>this</em><em> helps</em><em> </em><em>!</em>
