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Rainbow [258]
3 years ago
11

A driven gear with 60 teeth is driven by a driven gear of 30 teeth what is the VR of

Physics
1 answer:
noname [10]3 years ago
6 0

Answer:

VR=2

Explanation:

driven=60

driving=30

but VR=driven/driving

VR=60/30

VR=2

hence the velocity ratio VR is 2

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A 6.75 nC charge is located 1.99 m from a 4.46 nC point charge.
sladkih [1.3K]

Explanation:

Given that,

Charge 1, q_1=6.75\ nC=6.75 \times 10^{-9}\ C

Charge 2, q_2=4.46\ nC=4.46\times 10^{-9}\ C

The distance between charges, r = 1.99 m

To find,

The electrostatic force and its nature

Solution,

(a) The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

F=\dfrac{9\times 10^9\times 6.75\times 10^{-9}\times 4.46\times 10^{-9}}{(1.99)^2}

F=6.84\times 10^{-8}\ N

(b) As the magnitude of both charges is positive, then the force between charges will be repulsive.

Therefore, this is the required solution.

5 0
3 years ago
it is possible that the acceleration and velocity are perpendicular to each other? explain with example​
shusha [124]

Answer: Ok so We already know that velocity is on the x-axis.

Since acceleration = Force / Mass

Here the Force is downward due to the gravitational pull or we can say it is along y-axis.

Since acceleration is directly proportional to force, so acceleration is also along y-axis. This means that velocity & acceleration are perpendicular to each other.

Example:

Let us assume that an aeroplane is flying parallel to the horizontal plane. The aeroplane will experience the acceleration in several directions. One of them here is the gravitational pull which is perpendicular to the the apparent velocity. So the net velocity & its direction will depend upon the vector sum total of all the forces/acceleration acting on it. Also because of this gravitational pull the aeroplane rotates along with the earth, which is a proof that the force/g experienced by it does not go waste.

<h3>Hope this helps have a awesome day/night❤️✨</h3>

Explanation:

5 0
2 years ago
A man lifts a 120 kg barbell 2 m above the ground . What is the gain in gravitational PE of the barbell?
SpyIntel [72]

Answer:

2,352 Joules

Explanation:

At the ground, the barbell has a classical mechanical energy value of zero. There is no classical kinetic or potential energy for the barbell. The moment the man starts to lift the barbell, he does work on the barbell and transfers kinetic energy to it due to the motion. At its maximum height where the man lifts the barbell to a stop, the kinetic energy is zero because it transformed into gravitational potential energy stored in the gravitational field. Our reference point for potential was defined to be zero at the floor, therefore we can say that the gravitational potential energy at 2 meters is:

U=mgh=(120kg)(9.8m/s^2)(2m)=2,352J

7 0
2 years ago
an athlete is running at a constant velocity with a javelin held in his right hand.the force he is applying on thejavelin as he
mestny [16]
50 Nm
work=force*change in position
7 0
3 years ago
Which of the following is a U.S. unit of measurement?
inna [77]

B. Yard

the other answers C. & D. are metric A is a unit of temperature

8 0
3 years ago
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