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Dafna11 [192]
3 years ago
7

How much work is done when a porcelain vase with mass of 2.5 kg is lifted up 3 m to a shelf? (HINT- Weight can be used as Force

when the motion is up/down).
Physics
1 answer:
alexdok [17]3 years ago
8 0
Work = force x distance
F= 2.5
D= 3
Work = 2.5 x 3 =7.5
Work = 7.5 J
J=Jules (Jules is the unit uses to calculate work)
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Alice's friends Bob and Charlie are having a race to a distant star 10 light years away. Alice is the race official who stays on
hodyreva [135]

Solution :

The distance between the starting point and the end point, L_0 = 10 light years

But due to the relativistic motion of Bob and Charlie, the distance will be reduced following the Lorentz contraction. The contracted length will be different since they are moving with different speeds.

For Bob,

Speed of Bob's rocket with respect to Alice, L_b = 0.7  \ c

So the distance appeared to Bob due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_b^2}{c^2}$

$L_b=10\times \sqrt{1-0.49} \ Ly$

    $=7.1 \ Ly$

Therefore, the time required to finish the race by Bob is

$t_b = \frac{L_b}{V_b}$

  $=\frac{7.1 \ c}{0.7 \ c}$

  = 10.143 year

For Charlie,

Speed of Charlie's rocket with respect to Alice, L_c = 0.866 \ c

So the distance appeared to Charlie due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_c^2}{c^2}$

$L_b=10\times \sqrt{1-0.75} \ Ly$

    $=5 \ Ly$

The time required to finish the race by Charlie is

$t_b = \frac{L_c}{V_c}$

  $=\frac{5 \ c}{0.866 \ c}$

  = 5.77 year

5 0
3 years ago
What happens to the force between two charges if one of the charges are doubled?
Julli [10]

Answer:

The new force between the charges becomes double of the initial force.

Explanation:

The force acting between charge particles is given by :

F=k\dfrac{q_1q_2}{r^2}

k is electrostatic constant

r is distance between charges

If one of the charges are doubled, then, q₁ = 2q₁

The new force becomes,

F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F

So, the new force between the charges becomes double of the initial force.

7 0
4 years ago
True or False <br>One of the objections to the solar nebula theory is the angular momentum problem.
KengaRu [80]

Answer:

False, the angular momentum problem is not one of the objections to the solar nebular theory.

5 0
3 years ago
If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 33
RUDIKE [14]
66 g of element Y is needed since the ratio between element X and element Y is 1:2
5 0
3 years ago
If the mass of the cement is 15 000 kg, calculate the density of this cement sample in kgm-3
MrRa [10]

Explanation:

Hi there!

Mass of the container (m) = 15000 kg

Also from the figure;

Volume of the container (V) = l*b*h

{ From figure length = 2m , breadth = 1.1m, height = 2.5m}

So,

V = (2*1.1*2.5) m³

= 5.5m³

Then;

Density (d) = m/v

= 15000/5.5

= 2727.27 kgm³

Therefore, the density is 2727.27 kgm³.

Hope it helps!

5 0
2 years ago
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