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2 years ago

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1. A fraction that includes both a whole number and a proper fraction is known as? 2. A fraction where the numerator is bigger t

han the denominator is known as proper fraction. True or False ?

1 answer:

Ne4ueva [31]2 years ago

3 0

Answer:

1. Mixed fraction 2. false

I hope this helps

Step-by-step explanation:

You might be interested in

What is the answer of this question?

polet [3.4K]

Answer:

116

Step-by-step explanation:

8.2 / 2 = 4.1

a = $\sqrt{7^{2}-4.1^{2} } = 5.6736$

0.5 x 8.2 x 5.6736 = 23.2618

23.2618 x 5 = 116.309 = 116

7 0

3 years ago

1. A test-tube has a diameter of 3cm. How many turns would a piece of thread of length

Alex Ar [27]

So if we think of a test tube, it looks sort of like a cylinder. This means that its cross-section would be a circle. To find out how many turns a piece of thread would make around the test tube, we need to find the circumference of the test tube, then divide the length of the string by the circumference.

Step 1) Find the circumference

C = pi x diameter

C = 3.14 x 3

C = 9.42

Step 2) Divide the length of the string by the circumference

90.42 / 9.42 = 9.5987

The string would make approximately 9.60 turns around the test tube.

Hope this helps!! :)

6 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

I need help please it’s really hard and I don’t understand it

mr_godi [17]

The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.

We're told that HJ has length 7<em>x</em> - 27.

The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.

This means we have

7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)

Solve for <em>x</em> :

7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)

7<em>x</em> - 27 = 4<em>x</em> - 6

7<em>x</em> - 4<em>x</em> = 27 - 6

3<em>x</em> = 21

<em>x</em> = 21/3

<em>x</em> = 7

5 0

3 years ago

Simplify the product. Write your answer in standard notation 2y(5y^2 + 3)

GarryVolchara [31]

Answer:

10y^3+6y

Step-by-step explanation:

3 0

2 years ago