The number of Ml of a 0.40 %w/v solution of ,nalorphine that must be injected to obtain a dose of 1.5 mg is calculated as below
since M/v% is mass of solute in grams per 100 ml
convert Mg to g
1 g = 1000 mg what about 1.5 mg =? grams
= 1.5 /1000 = 0.0015 grams
volume is therefore = 100 ( mass/ M/v%)
= 100 x( 0.0015/ 0.4) = 0.375 ML
Answer:
M=0.15
Explanation:
138 g AgNO -> 1 mol AgNO
10 g AgNO -> x
x= (10 g AgNO * 1 mol AgNO)/138 g x=0.07 mol AgNO
450 mL=0.45 L
M= mol solute/L solution
M= 0.07 mol AgNO/0.45L
M=0.15
Answer:
2Fe + 3Cl2 → 2FeCl3
Explanation:
Fe + Cl2 —> FeCl3
There are 3atoms of Cl on the right side and 2 atoms on the left side. Therefore, to balance Cl put 2 in front of FeCl3 and put 3 in front of Cl2 as shown below:
Fe + 3Cl2 → 2FeCl3
Now, we see clearly that there are 2 atoms of Fe on the right side and 1 on the left side. This can be balanced by putting 2 in front of Fe as shown below:
2Fe + 3Cl2 → 2FeCl3
Now the equation is balanced.
