Which computation could be used to find the area of this poster?

The sum of two integers with different signs is eight give to possible integers that fit this description

Soloha48 [4]

An easy way is to do this
the 2 numbers are -x and x+8 where x is an integer

we can generate lots of numbers this way

example
-1 and 9
-2 and 10

8 0

3 years ago

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

4 years ago

Points are: A= (-2,7)B= (3,5)C= (1,0) To show that the triangle is a right triangle, show that the sum of the squares of the len

Gala2k [10]

The sum of the squares of the lengths is 58

The square of length of the hypotenuse is 58

From the question, we have

AB² = (-2-3)² +(7-5)²= 25+4 =29

BC² = (3-1)²+(5-0)²=4+25=29

AC² = (-2-1)²+(7-0)² = 9+49 = 58

Here we can see that,

AB²+BC² = AC²

The sum of the squares of the lengths of two sides (the legs) equals the square length of the third side (hypotenuse).

the sum of the squares of the lengths = AB²+BC² =29+29 = 58

the square of length of the hypotenuse= 58

Pythagoras Theorem:

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

To learn more about pythagoras theorem visit: brainly.com/question/343682

#SPJ9

5 0

1 year ago

How to work out problem 6 3/4 - 8 2/3

Dafna11 [192]

Answer:

-23/12

Step-by-step explanation:

6 3/4-8 2/3

=27/4-26/3

=3*27-26*4/12

=81-104/12

=-23/12

8 0

4 years ago

Read 2 more answers

Explain how you can use place value to describe how 0.05 and 0.005 compare

Dovator [93]

.05 is larger than .005 because larger numbers are always to the left and smaller numbers are always to the right

3 0

4 years ago