Answer:
C.0.28 V
Explanation:
Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:
The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:
Cu²⁺ + 2e⁻ → Cu E° = 0.52V
Ag⁺ + 1e⁻ → Ag E° = 0.80V
As the Cu will be oxidized:
Cu → Cu²⁺ + 2e⁻
The cell potential is:
E°Cell = E°cathode(reduced) - E°cathode(oxidized)
E°cell = 0.80V - (0.52V)
E°cell = 1.32V
Right answer is:
<h3>C.0.28 V
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Answer:
K2CrO4
Explanation:
To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:
K = 1.04/39.0983 = 0.027
Cr = 0.70/51.9961 = 0.013
O = 0.86/15.999 = 0.054
We now divide by the smallest which is the number of moles of the Chromium
K = 0.027/0.013 = 2
Cr = 0.013/0.013 = 1
K = 0.054/0.013 = 4 approximately
The empirical formula is thus:
K2CrO4
Answer:
You fill up the 5 liter bottle. Then pour the contents from the 5 liter to the 3 liter till the 3 liter is full. Once the 3 liter bottle is full, what is left in the 5 liter bottle is 2 liters. Then you empty out the 3 liter until it matches the height of the 5 liter. Pour the remaining contents of the 3 liter bottle in the 5 liter bottle to get exactly 4 liters.
Answer:Ionic compounds form when positive and negative ions share electrons and form an ionic bond. ... The positive ion, called a cation, is listed first in an ionic compound formula, followed by the negative ion, called an anion. A balanced formula has a neutral electrical charge or net charge of zero.
Explanation:Simple ions:
Perchlorate ClO4- IO3-
Chlorate ClO3- BrO3-
Chlorite ClO2-
Hypochlorite OCl- OBr-