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Ber [7]
3 years ago
6

Which of the following procedures demonstrates repetition? A. Jeremiah measures the mass of five different strips of metal. He p

laces the strips in five different test tubes filled with hydrochloric acid. He observes if heat and bubbles are produced after the metal strips and acid are combined. B. Cynthia monitors the growth rate of her pet turtle. She measures the length and weight of her turtle every Sunday over the course of six months. C. Marco places a toy car at the top of a ramp. He releases the car and measures how long it takes for the car to reach the bottom of the ramp. Then, he returns the car to the top of the ramp, releases the car again, and makes an additional measurement. D. Kasey performs a scientific investigation on the effects of using soda instead of water to hydrate plants. Caleb uses Kasey's procedure and performs the same experiment during the following month.
Chemistry
2 answers:
lara31 [8.8K]3 years ago
7 0

The answer is C bc i did it already.

viktelen [127]3 years ago
3 0

Answer:Marco places a toy car at the top of a ramp. He releases the car and measures how long it takes for the car to reach the bottom of the ramp. Then, he returns the car to the top of the ramp, releases the car again, and makes an additional measurement.

Explanation:

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Chlorine has seven electrons in its valence shell. It accepts an electron to complete its octet and becomes a chlorine ion (Cl-)
KIM [24]
The correct answer here is B - when chlorine accepts an electron to complete its octet and becomes a chlorion ion it becomes an Anion. An anion is a negatively charged ion. Chloride ions are an important electrolyte within the body.
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2 years ago
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

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3 years ago
Which is a density independent factor limiting popultion growth
shusha [124]

The amount the amount of space a population has to grow in would be a limiting factor.


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What is the volume of the sphere? Round your answer<br> to the nearest tenth.<br> cm
myrzilka [38]

Answer:

volume

v = 4/3π r^3

Explanation:

it isn't specific enough but that is the equation of how to get any volume

volume equals four thirds times pi times radios to the power of three

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Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.
frosja888 [35]

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If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

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