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2 years ago

What is the ending substance of? C + H2O → CO + H2

Chemistry

2 answers:

sweet-ann [11.9K]2 years ago

8 0

Carbon monoxide (CO) and hydrogen (H2).

SOVA2 [1]2 years ago

7 0

H2=Hydrogen is the answer to what is H2 in chemistry.

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Which of the following statements most likely

cupoosta [38]

Answer:

Forming a problem requires the scientist to use creativity to imagine new solutions.

Explanation:

Albert Einstein remains a critically prominent figure who conducted remarkable, ground-breaking research that not only formed the foundations of modern physics but also strongly affected the scientific world. It is difficult to teach imagination but it can be harnessed and accepted. Nothing incites our imaginative impulses we love more than the prospect of immediate creative inspiration. And creativity hits its full potential when paired with the experience, insights, and skills people gained by questioning the real-life problems.

6 0

2 years ago

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A balanced chemical reaction obeys the law of...

Anit [1.1K]

Answer: (C) conservation of matter

Solution: Law of conservation of matter or mass states that' total mass of the reactants should always be equal to the total mass of the product that is the total mass is remained conserved in a chemical reaction.

A balanced chemical equation always follow this law.

For example:

$2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$

Mass of hydrogen = 1 g/mol

Mass of Oxygen = 16 g/mol

Total mass on the reactants = 2(2×1)+(2×16)= 36g/mol

Total mass on the product side = 2[(2×1) +16] = 36 g/mol

As,

Mass on reactant side = Mass on the product side

Therefore, a balanced chemical reaction follows Law of Conservation of mass.

4 0

3 years ago

Read 2 more answers

when 10 moles of sodium reacts with excess oxygen for 60 minutes, only 3 moles of sodium remains in 1000 millimeters of H20. Wha

diamong [38]

That would be....................

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2 years ago

Help asap on a time crunch

marusya05 [52]

Answer:

only sodium chloride compounds MOST LIKELY products of the reaction between sodium metal and chlorine gas.

Correct answer - C

Explanation:

A solid sodium metal reacts with gaseous form of chlorine gas to form a solid sodium chloride.

This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.

As a result, an ionic compound solid sodium chloride is formed.

The chemical reaction of formation sodium chloride is as follows.

$2Na(s)+Cl_{2}(g) \rightarrow 2NaCl(s)$

Therefore, only sodium chloride compounds MOST LIKELY products of the reaction between sodium metal and chlorine gas.

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3 years ago

Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid

Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

$35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol$

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

$\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M$

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb) where Cb is the initial concentration of the base

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0

2 years ago