I think it would be better control of fusion reactions.
So here we are given that the the velocity of the proton ( V ) is 2.0 ×
meters / second, with a magnetic field of strength 5.5 ×
tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....
F = q( V × B ),
F = q v B( sin ∅ ),
F = q v B( sin( 90 ) )
.... they form the following formula. Let's go through each of the variables in our formula here -
{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 ×
coulombs ), B = magnetic field }
All we have to do now is plug and chug,
F = ( 1.602 ×
)( 2.0 ×
)( 5.5 ×
) = ( About ) 1.8 ×
Newtons
Answer:
41.67 mol
Explanation:
1 Litre of water = 1000g
Mole = mass / molar mass
Mass of 1 L of water = 1000 g
Molar mass of water (H2O) :
(H = 1, O = 16)
H2O = (1 * 2) + 16 = (2 + 16) = 18g/mol
Amount of water consumed = (3/4) of 1 litre
= (3/4) * 1000g
= 750g
Therefore mass of water consumed = 750g
Mole = 750g / 18g/mol
Mole of water consumed = 41.6666
= 41.67 mol