Answer:
%age Yield = 51.45 %
Solution:
Step 1: Convert Kg into g
68.5 Kg CO = 68500 g CO
8.60 Kg H₂ = 8600 g
Step 2: Find out Limiting reactant;
The Balance Chemical Equation is as follow;
CO + 2 H₂ → CH₃OH
According to Equation,
28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂
So,
68500 g CO will react with = X g of H₂
Solving for X,
X = (68500 g × 4 g) ÷ 28 g
X = 9785 g of H₂
It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.
Step 3: Calculate Theoretical Yield
According to equation,
4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol
So,
8600 g H₂ will produce = X g of CH₃OH
Solving for X,
X = (8600 g × 32 g) ÷ 4 g
X = 68800 g of CH₃OH
Step 4: Calculate %age Yield
%age Yield = Actual Yield ÷ Theoretical Yield × 100
Putting Values,
%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100
%age Yield = 51.45 %
The formula for that compound is AlN
Answer:
6
Explanation:
The coordination number of a particular crystal structure arrangement is defined as the number of nearest neighbor atoms or ions surrounding an atom or ion.
We must note that in salts of the type MX, the coordination number of each ion must be equal. The structure of LiCl is built by placing each unit cell next to another such that ions residing in the corner, edge or face sites are shared between adjacent unit cells. The LiCl is in FCC arrangement.
Hence in LiCl, each Li+ ion is surrounded by 6 chloride ions.
Answer:
The value is 
Explanation:
From the question we are told that
The initial volume of the fluorocarbon gas is 
The final volume of the fluorocarbon gas is
The initial temperature of the fluorocarbon gas is 
The final temperature of the fluorocarbon gas is 
The initial pressure is 
The final pressure is 
Generally the equation for adiabatically reversible expansion is mathematically represented as
![T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }](https://tex.z-dn.net/?f=T_2%20%3D%20%20T_1%20%20%2A%20%5B%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%5D%5E%7B%5Cfrac%7BR%7D%7BC_v%7D%20%7D)
Here R is the ideal gas constant with the value
So
![248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }](https://tex.z-dn.net/?f=248.44%20%3D%20%20%20298.15%20%20%2A%20%5B%20%5Cfrac%7BV%7D%7B2V%7D%20%5D%5E%7B%5Cfrac%7B8.314%7D%7BC_v%7D%20%7D)
=> 
Generally adiabatic reversible expansion can also be mathematically expressed as
=>![[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}](https://tex.z-dn.net/?f=%20%5B%2081.840%20%2A10%5E3%5D%20%5B2V%5D%5E%7B%5Cgamma%7D%20%3D%20%5B202.94%20%2A10%5E3%5D%20V%5E%7B%5Cgamma%7D)
=> 
=> 
So
=>
Answer:
<h2>3.31 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 23.2 g
volume = final volume of water - initial volume of water
volume = 62 - 55 = 7 mL
We have
We have the final answer as
<h3>3.31 g/mL</h3>
Hope this helps you
