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svet-max [94.6K]
2 years ago
8

The atmospheric pressure on the surface of Venus is 6.84X10^4. Calculate the atmospheric pressure in atm and torr. Round each of

your answers to 3 significant digits.
Chemistry
1 answer:
quester [9]2 years ago
5 0

Answer:

0.675 atm

513 Torr

Explanation:

Given is that, the atmospheric pressure on the surface of Venus is

6.84 X 10⁴ Pa.

1 atm (atmospheric pressure) is equal to 101325 pascal (Pa).

To convert divide the pressure value by 101325.

Pressure in atm = \frac{6.84 \times 10^{4} }{101325}

= 0.675055 atm

Rounding it off to 3 significant digits: 0.675 atm

Now,  one Torr is 133.322 Pa. For conversion, divide the pressure value by 133.322.

Pressure in Torr = \frac{6.84 \times 10^{4} }{133.322}

=513.04219 Torr

Rounding it off to 3 significant digits: 513 Torr

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borishaifa [10]

Answer:

Ca(OH)2 will not precipitate because Q<Ksp

Explanation:

Ksp for Ca(OH)2 has already been stated in the question as 8.0 x 10-8mol2dm-6

The value of the reaction quotient depends heavily on the concentration of the reactants. As the initial concentration of the calcium carbide decreases considerably, the reaction quotient decreases until Q<Ksp hence the Ca(OH)2 will not precipitate from solution.

The reaction equation is:

CaC₂(s) + H₂O ⇒ Ca(OH)₂ + C₂H₂

From

Ca(OH)2= Ca2+ + 2OH-

Concentration of solution= 0.064×1/64= 1×10-3

Since [Ca2+] = 1×10-3

[OH-]= (2×10-3)^2= 4×10^-6

Hence Q= 4×10^-9

This is less than the Ksp hence the answer.

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2 years ago
1. How many moles of iron is needed to react with sulfur in order to produce 8.6 moles
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<em>2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide</em>

<em />

Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:

8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =

<h3>17.2 moles of Iron are required</h3>
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