1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
drek231 [11]
4 years ago
10

A positive and a negative charge are released from rest in vacuum. They move toward each other. As they do: A positive and a neg

ative charge are released from rest in vacuum. They move toward each other. As they do: A negative potential energy becomes less negative. A positive potential energy becomes a negative potential energy. A positive potential energy becomes more positive. A negative potential energy becomes more negative. A positive potential energy becomes less positive. SubmitRequest Answer
Physics
1 answer:
Pachacha [2.7K]4 years ago
4 0

Answer:

A negative potential energy becomes more negative

Explanation:

Let the charges be - Q₁ and Q₂ . Let the distance between them be d .

Potential energy = k -Q₁x Q₂ / R

= - KQ₁ Q₂ / R

Now if the magnitude of R decreases , the magnitude of potential energy increases . So we see that the negative  potential energy becomes more negative .  

You might be interested in
Why is measuring the duration of a number of swings a better way to determine the period of a pendulum than by measuring a singl
Alekssandra [29.7K]

Answer:

It is to reduce the expected relative error of the measurement.

Explanation:

If there was a way to measure without error, this method would be unnecessary. In practice, the pesky error is always there. The sources are varied: inexact instrument, small inaccuracies in starting/stopping the timer, etc. But, it is reasonable to assume that such an error is random and has an expected spread that is <em>independent</em> of the actual duration of measurement. Under such assumptions, the methods offers a great advantage:

Let ε denote an additive measurement error. Let the error be random, symmetric (negative/positive), distributed in some fixed range independent of the actual measured value. The error represents an additive component in our measurement, i.e., (measurement) = (true value) + (error). In the case of one period T, we get to measure the duration T':

T' = T + \epsilon

so the relative error is

\frac{|T'-T|}{T}=\frac{|T+\epsilon-T|}{T}=\frac{|\epsilon|}{T}

In a separate experiment, suppose you measure n periods. Same error applies:

T_n'=n\cdot T+\epsilon

we can get a single period by dividing the measured value by n:

\frac{T_n'}{n}=\frac{n\cdot T +\epsilon}{n}=T+\frac{\epsilon}{n}

and the relative error of such a result will be:

\frac{|T+\frac{\epsilon}{n}-T|}{T}=\frac{|\epsilon|}{n\cdot T}

which is n times smaller than the relative error of the single measurement above. The more periods are included in the measurement, the smaller the expected error!

5 0
3 years ago
A worker pushes a 200-N box (weight of box, you have to find mass) resting on a level floor with a force of 30 N. What is the ac
QveST [7]

For the problem we will apply the concepts related to Newton's second law. Recall that this is defined as the product between mass and acceleration, and that in special cases, when the acceleration is equivalent to the force of gravity, the force is equivalent to the weight of the person. From these relationships we will find the mass, and then the acceleration with the given force.

F_w = mg

Here,

F_w= Force

m = Mass

g = Gravity

Replacing and rearranging we have that the mass is,

m = \frac{F_w}{g} = \frac{200}{9.81}

m = 20.387kg

Now using the value of the force, but solving for the acceleration with the previous value of the mass we have,

F = 30N

a = \frac{F}{m}

a = \frac{30}{20.387}

a = 1.47m/s^2

Therefore the acceleration of the box is 1.47m/s^2

8 0
3 years ago
shows a map of Olivia's trip to a coffee shop. She gets on her bike at Loomis and then rides south 0.9mi to Broadway. She turns
Andreas93 [3]

The  magnitude of the total displacement of her trip is 2.2 miles.

<h3>Total displacement of Olivia's trip</h3>

The magnitude of the total displacement of her trip is calculated as follows;

Total east journey = 0.8 mi + 1.2 mi = 2 mi

Resultant displacement = √(y² + x²)

Resultant displacement = √(0.9² + 2²)

Resultant displacement = 2.2 mi

Thus, the  magnitude of the total displacement of her trip is 2.2 miles.

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
2 years ago
How do you know the speed of an electromagnetic wave in a vacuum?
Ivenika [448]
The speed of electromagnetic waves in a vacuum is the same as the speed of light. It can be measured by finding the frequency and wavelength of two different waves, and then by that correlation, the speed of the waveform.
Hope this helps you (:
7 0
4 years ago
SERIOUSLY HELP NOWWW LIKE NOWW I REALLY NEED THIS ANSWERED
Orlov [11]

Answer:

the second one Test the rate of decay of specific elements in rock samples.

4 0
3 years ago
Other questions:
  • Describe 3 reason ancient astronomers used the movement of the skies <br>​
    7·1 answer
  • What is the Coriolis Force?
    7·1 answer
  • Imagine you are on a roller coaster, riding a skateboard, or running across the ball field. What are some clues that you are mov
    15·1 answer
  • A large semi-truck, with mass 31x crashes into a small sedan with mass x . If the semi-truck exerts a force F on the sedan, what
    13·1 answer
  • Which is not a way to accelerate an object?
    7·1 answer
  • A very hard rubber ball (m = 0.5 kg) is falling vertically at 4 m/s just before it bounces on the floor. The ball rebounds back
    12·1 answer
  • The calculated value of static friction
    9·1 answer
  • 7. What does the changing colour perceived by the person as the filter changes indicate to you
    12·1 answer
  • What happens to light when its wavelength changes?
    13·1 answer
  • Use the diagram to answer the following physics questions:
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!