Answer:
The maximum velocity is 0.377 m/s
Explanation:
Please, the solution is in the Word file attached
Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.
Explanation: I hoped that helped!!
The height at time t is given by
h(t) = -4.91t² + 34.3t + 1
When the ball reaches maximum height, its derivative, h'(t) = 0.
That is,
-2(4.91)t+34.3 = 0
-9.82t + 34.3 = 0
t = 3.4929 s
Note that h''(t) = -9.82 (negative) which confirms that h will be maximum.
The maximum height is
hmax = -4.91(3.4929)² + 34.3(3.4929) + 1
= 60.903 m
Answer:
The ball attains maximum height in 3.5 s (nearest tenth).
The ball attains a maximum height of 60.9 m (nearest tenth)
Hi, thank you for posting your question here at Brainly.
This problem could be solved using this equation:
Diffraction limit = 1.22*wavelength/diameter
diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m
Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
