Answer:
So then we will have at least 75% of the data within two deviations from the mean 
.
So then the interval would be (97.14, 99.5)
Explanation:
Previous concepts
Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean. "
If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.
And the general formula is (1-1/k^2) represent the fraction of the data within the mean .
Solution to the problem
For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:
So then we will have at least 75% of the data within two deviations from the mean .
For the other part we have the mean and deviation provided 
the interval would be:
So then the interval would be (97.14, 99.5)
Answer:
Option 2. √3 x V
Explanation:
Let the velocity of satellite orbiting Earth at r be V
Let the velocity of the satellite orbiting at 3r be V1
V (orbiting at r) = √(2gr)
V1 (orbiting at 3r) = √(2g3r)
Now let us find the ratio of V1(orbiting at 3r) to V(orbiting at r) .
This is illustrated below
V1 / V = √(2g3r)/√(2gr)
V1 / V = √3
Cross multiply to express in linear form
V1 = V x√3
V1 = √3 x V
From the above illustrations, we can see that the velocity of the satellite when it is moved to an orbital radius of 3r is: √3 x V
Radio waves are electromagnetic waves with wavelengths of 1 millimeter or more . . . frequencies of 300 GHz or less.
Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
