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ddd [48]
3 years ago
10

Adrian 80.0kg jumps out of an airplane at an altitude of 1.00×10^3m. After his parechute deploys, the adrian lands with a veloci

ty of 5.00m/s. Using the work kinetic energy theorem, find the energy that was lost to air resistence to during this jump. (g=9.81m/s^2)
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

-- Before Adrian left the airplane, his gravitational potential energy was

(mass) x (gravity) x (height) = (80kg) x (9.81m/s²) x (1,000m) = 784,800 joules


-- When he reached the ground, his kinetic energy was

(1/2) x (mass) x (speed)² = (40kg) x (5m/s)² = 1,000 joules


-- Between the airplane and the ground, the Adrian lost

(784,800 joules) - (1,000 joules) = 783,800 joules 

Where did all that energy go ?
Energy never just disappears.  If it's missing, it had to go somewhere.

The Adrian used  783,800 joules of energy to push air our of his way
so that he could continue his parachute jump, and reach the ground
in time to be home for dinner. 
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7 0
3 years ago
A bullet is fired with a muzzle velocity of 1178 ft/sec from a gun aimed at an angle of 26° above the horizontal. Find the horiz
dalvyx [7]

Answer:

1058.78 ft/sec

Explanation:

Horizontal Component of Velocity; This is the velocity of a body that act on the horizontal axis. I.e Velocity along x-axis

The horizontal velocity of a body can be calculated as shown below.\

Vh = Vcos∅.......................... Equation 1

Where Vh = horizontal component of the velocity, V = The velocity acting between the horizontal and the vertical axis, ∅ = Angle the velocity make with the horizontal.

Given: V = 1178 ft/sec, ∅ = 26°

Substitute into equation 1

Vh = 1178cos26

Vh = 1178(0.8988)

Vh = 1058.78 ft/sec

Hence the horizontal component of the velocity = 1058.78 ft/sec

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3 years ago
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4 years ago
The temperature of a 2.0kg block increases by 5C when 2000 J of thermal energy are added to the block. What is the specific heat
vitfil [10]

Explanation:

Q=mc(T2-T1)

or

q = mcΔT ,

where m is the mass of the sample,

c is the specific heat,

and ΔT is the temperature change.

Q=2.0 × 2000 × 5

Q=20000J⋅kg −1 ⋅K −1

I hoped I helped pls rate as brainliest

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15.3

+1.285

---------------

Answer = 16.585

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