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kakasveta [241]
3 years ago
15

What is the same about the EM categories? What is different?

Physics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

All 3 are CSS unit sizes which we can use for margins, fonts, borders etc.

Exp

CSS has four different unit sizes. These are:

Pixels (px)

Points (pt)

Ems (em)

Percentages(%)

These units are divided into two different groups. They are fixed and relative.

Pixels and points are fixed , whereas em and percentages are relative unit sizes. Relative unit sizes are good when creating scalable layouts.

Ems (em):

An em is a CSS unit that measures the size of a font. Originally, the em was equal to the width of the capital letter M, which is where its name originated.

It stands for "emphemeral unit" which is relative to the current font size.

The "em" is a scalable unit that  is used in web document media. Ems have mobile-device-friendly nature.

Pixels (px):

Pixels are fixed-size units that are used in screen media. One pixel is equal to one dot in computer. The problem with pixel unit is that it is not relative .

Points (pt):

Point values are only for print. A point is a unit of measurement use for real-life ink on paper. Generally, 72pts= 1 inch which is one real-life inch like on  a ruler. Point  is not recommended to use in web pages.

Generally, 1em=16px=12pt=100% if the body size is 100%.

Relative unit sized fonts change and fixed unit sized fonts remain the same.

For example,

body { font-size: 100%}

p{font-size: 16px}

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A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the s
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Complete question is;

A force stretches a wire by 0.60 mm. A second wire of the same material has the same cross section and twice the length.

a) How far will it be stretched by the same force?

b) A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the same force?

Answer:

0.15 mm

Explanation:

According to Hooke's Law,

E = Stress(σ)/Strain(ε)

Where E is youngs modulus

Formula for stress is;

Stress(σ) = Force(F)/Area(A)

Formula for strain is;

Strain(ε) = Change in length/original length = (Lf - Li)/Li

We are also told that a second wire of the same material has the same cross section and twice the length.

Thus;

Rearranging Hooke's Law to get the constants on one side, we have;

F/(AE) = ε

Thus from the conditions given;

ε1 = 0.6/Li

ε2 = (Change in length)/(2*Li)

And ε1 = ε2

Thus;

0.6/Li = Change in length/(2*Li)

Li will cancel out and we now have;

Change in length = 2 × 0.6 = 1.2 mm

Finally, we are told A third wire of the same material has the same length and twice the diameter as the first.

Area of a circle;A1 = πd²/4

Now, we are told d is doubled.

Thus, new area of the new circle is;

A2 = π(2d)²/4 = πd²

Rearranging Hooke's Law,we have;

F/A = εE

Since F and E are now constants, we have;

F/E = constant = Aε

Thus;

A1(ε1) = A2(ε2)

A1 = πd²/4

e1 = 0.60/Li

A2 = πd²

e2 = Change in length/Li

Thus;

((πd²/4) × 0.6)/Li = (πd² × Change in length)/ Li

Rearranging, Li and πd² will cancel out to give;

0.6/4 = Change in length

Change in length = 0.15 mm

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