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2 years ago

What is the same about the EM categories? What is different?

Physics

1 answer:

cricket20 [7]2 years ago

8 0

Answer:

All 3 are CSS unit sizes which we can use for margins, fonts, borders etc.

Exp

CSS has four different unit sizes. These are:

Pixels (px)

Points (pt)

Ems (em)

Percentages(%)

These units are divided into two different groups. They are fixed and relative.

Pixels and points are fixed , whereas em and percentages are relative unit sizes. Relative unit sizes are good when creating scalable layouts.

Ems (em):

An em is a CSS unit that measures the size of a font. Originally, the em was equal to the width of the capital letter M, which is where its name originated.

It stands for "emphemeral unit" which is relative to the current font size.

The "em" is a scalable unit that is used in web document media. Ems have mobile-device-friendly nature.

Pixels (px):

Pixels are fixed-size units that are used in screen media. One pixel is equal to one dot in computer. The problem with pixel unit is that it is not relative .

Points (pt):

Point values are only for print. A point is a unit of measurement use for real-life ink on paper. Generally, 72pts= 1 inch which is one real-life inch like on a ruler. Point is not recommended to use in web pages.

Generally, 1em=16px=12pt=100% if the body size is 100%.

Relative unit sized fonts change and fixed unit sized fonts remain the same.

For example,

body { font-size: 100%}

p{font-size: 16px}

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antiseptic1488 [7]

Answer:

The value of the distance is $\bf{14.52~cm}$ .

Explanation:

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$v = \omega \sqrt{A^{2} - x^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`~(1)$

where, $\omega$ is the angular frequency, $A$ is the amplitude of the oscillation and $x$ is the displacement of the particle at any instant of time.

The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., $x = 0$ .

The maximum velocity( $\bf{v_{m}}$ ) is

$v_{m} = \omega A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Divide equation (1) by equation(2).

$\dfrac{v}{v_{m}} = \dfrac{\sqrt{A^{2} - x^{2}}}{A}~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)$

Given, $v = 0.25 v_{m}$ and $A = 15~cm$ . Substitute these values in equation (3).

$&& \dfrac{1}{4} = \dfrac{\sqrt{15^{2} - x^{2}}}{15}\\&or,& A = 14.52~cm$

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3 years ago

A car is moving 5.82M/S when it accelerates at 2.35M/S^2for 3.25S. What is its final velocity?

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Answer:

Explanation:

vf=vi+at

vi=5.82 m/s

a=2.35 m/s2

t=3.25 s

vf=5.82+2.35*3.25

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vf=13.46

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2 years ago

Sound waves with frequency higher that 20,000 Hz are referred to as

Solnce55 [7]

<span>Sound waves with frequency higher that 20,000 Hz are referred to as "Ultrasonic"

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2 years ago

Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.6×104 m/s when at a distance

xz_007 [3.2K]

Answer:

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

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v₂ = ?

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K.E₁ + P.E₁ = K.E₂ + P.E₂

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$v_2= \sqrt{(1.6\times 10^4)^2 +2\times 6.67 \times 10^{-11}\times 1.99 \times 10^{30}(\dfrac{1}{4.8\times 10^{10}}-\dfrac{1}{2.7\times 10^{11}})}$

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2 years ago

what is the magnitude of the electric force between charges of 0.25 C and 0.11 C at a separation of 0.88 m? if the separation be

leonid [27]

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If the separation between the charges is increased then the magnitude of the force will increase in fact how the distance is being used in that formula.

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