Answer:
this is a simple application of Newton's 2nd Law: F = ma.
F = 0.023(25)
So,
F =0.575 N.
Therefore
The answer is A.
If rounded up/off.
Explanation:
HOPE IT HELPS.
PLEASE MARK AS BRAINLIEST.
9700 because 682 rounds to 700
An object moving in a circular path has centripetal acceleration. <em>(A)</em>
I believe it’s stay in motion if it’s not acted on by an unbalanced force
Answer:
F = 156.3 N
Explanation:
Let's start with the top block, apply Newton's second law
F - fr = 0
F = fr
fr = 52.1 N
Now we can work with the bottom block
In this case we have two friction forces, one between the two blocks and the other between the block and the surface. In the exercise, indicate that the two friction coefficients are equal
we apply Newton's second law
Y axis
N - W₁ -W₂ = 0
N = W₁ + W₂
as the two blocks are identical
N = 2W
X axis
F - fr₁ - fr₂ = 0
F = fr₁ + fr₂
indicates that the lower block is moving below block 1, therefore the upper friction force is
fr₁ = 52.1 N
fr₁ = μ N
a
s the normal in the lower block of twice the friction force is
fr₂ = μ 2N
fr₂ = 2 μ N
fr₂ = 2 fr₁
we substitute
F = fr₁ + 2 fr₁
F = 3 fr₁
F = 3 52.1
F = 156.3 N
