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3 years ago

Help with this review pls!!

Physics

2 answers:

o-na [289]3 years ago

5 0

40 50 60 85 954 746 ity

Anna35 [415]3 years ago

5 0

Answer:

The 2 forces are a Push and a Pull

Mass is the resistance of change in speed or position when adding force.

Weight is the force of gravity

Tension Force is the pulling force transmitted through a string cable or chain. The formula for this is T = mg + ma.

It gives the particle the same acceleration as all those actual forces together as described by the Newton's second law of motion.

An unbalanced force is when there is 2 forces on opposites of an object both are adding force but one side is stronger than the other.

Friction is a force that heats things up. This happens when we rub our hands together and the heat that is generated from the friction makes our hands warmer.

Static friction is what keeps the box from moving without being pushed, and it must be overcome with a sufficient opposing force before the box will move. Kinetic friction (also referred to as dynamic friction) is the force that resists the relative movement of the surfaces once they're in motion.

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Which form of the law of conservation of energy describes the motion of the block when it slides from the top of the table to th

Mnenie [13.5K]

By definition we have that the energy at the top of the ramp is equal to the energy at the bottom of the ramp. This is due to the principle of energy conservation.

We have then:

$E1 = E2$

The energy at the top is only potential energy:

$E1 = mgh$

Where,

m: mass
g: acceleration of gravity
h: vertical height of the ramp

The energy when it falls is transformed into kinetic energy and therefore:

$E2 = \frac {1} {2} mv ^ 2$

Where,

v: object speed.

Therefore we have:

$mgh = \frac {1} {2} mv ^ 2$

Answer:

The potential energy is transformed into kinetic energy.

$mgh = \frac {1} {2} mv ^ 2$

3 0

3 years ago

Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling

quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (Sp is for Spot, F is for Fido and St is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

$\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0$ (1)

$\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0$ (2)

If we know that $F_{F} = 20\,N$ , $F_{Sp} = 30\,N$ and $\theta_{F} = 63^{\circ}$ , then the components of the force done by Steinberg on the chewing toy is:

$F_{St,x} = -F_{F}\cdot \cos \theta_{F}$

$F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}$

$F_{St, x} = -9.080\,N$

$F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}$

$F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}$

$F_{St, y} = 12.180\,N$

The magnitud of the force is determined by Pythagorean Theorem:

$F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}$

$F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}$

$F_{St} \approx 15.192\,N$

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)$