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muminat
3 years ago
13

Because of the anode heel effect, where is the intensity of the x-ray beam the greatest?

Physics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

Along the anode-cathode axis

Explanation:

The Anode Heel Effect, in an X-ray tube states that the direction of emission of X-rays by the anode along the cathode-anode axis causes a variation in the intensity of X-rays.

The geometry of the anode causes the X-ray emitted perpendicular to the cathode-anode axis less intense than the X-rays emitted towards the cathode along the axis.

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What does the area between the line and the x axis represent on a velocity vs time graph
pychu [463]

the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period

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5 0
3 years ago
PLEASE HELP ASAP!!!!!
Igoryamba

While falling, both the sheet of paper and the paper ball experience air resistance. But the surface area of the sheet is much more than that of the spherical ball. And air resistance varies directly with surface area. Hence the sheet experiences more air resistance than the ball and it falls more slowly than the paper ball.

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8 0
3 years ago
Give one example of a question that science would not be able to test.
Strike441 [17]
DOES GOD EXIST? That is one of the best.
8 0
3 years ago
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A projectile is fired at a velocity of 50 m/s straight into the air. What is the velocity of the projectile when the objects dis
Arisa [49]

Answer:

the final velocity of the object is 53.04 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

displacement of the object, d = 16 m

let the final velocity of the object = v

Apply the following kinematic equation to determine the final velocity of the projectile.

v² = u² + 2gd

v² = 50² + (2 x 9.8 x 16)

v² = 2813.6

v = √2813.6

v = 53.04 m/s

Therefore, the final velocity of the object is 53.04 m/s.

8 0
3 years ago
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass
devlian [24]

Answer:

The velocity of the recoil is v=1.001 \frac{m}{s}

Explanation:

Kinetic Energy

m_{bullet}*v_{bullet}=m_{gun}*v_{recoil}\\m_{gun}= 15.0kg+3.6kg

The mass of th gun is the both mass the shotgun and the arm shoulder combination

m_{bullet}=0.049kg\\v_{bullet}=380\frac{m}{s} \\m_{bullet}*v_{bullet}=m_{gun}*v_{recoil}\\0.049kg*380\frac{m}{s}=(15.kg+3.6kg)* v_{recoil}\\v_{recoil}=-\frac{18.62 kg \frac{m}{s} }{18.6 kg}\\ v_{recoil}=-1.0010 \frac{m}{s}

The velocity is negative because is in opposite direction of the bullet

6 0
3 years ago
Read 2 more answers
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