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Otrada [13]
4 years ago
8

A tissue box is in the shape of a rectangular prism with an area of 528 in.³ the length of the box of tissues is 12 inches in th

e height is 5 1/2 inches what is the width of the box of tissues? Somebody please help ASAP!! Thanks!!
Mathematics
1 answer:
iris [78.8K]4 years ago
5 0
Pu$$y is very good save it! you'll need it later in life! trust me!
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How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
If 4+h=7 what is the value of 5h?
Art [367]

Answer

5h=15

Step-by-step explanation:

h = 7 - 4 = 3 therefore 5(3)=15

4 0
4 years ago
Read 2 more answers
A jar contains 5 blue marbles, 6 yellow marbles, and 4 green marbles. What is the probablity of randomly choosing a yellow marbl
marusya05 [52]

First, you need to choose a yellow marble. That is 6/15.

Next, you need to choose a blue marble. That is 5/14, because 1 yellow marble would have been "chosen" already.

So the probability altogether is 6/15 * 5/14 = 1/7, or about 14%.

4 0
3 years ago
What the answer now to the question
Lostsunrise [7]

Step-by-step explanation:

<em>Hello</em><em>!</em><em>!</em><em>!</em>

<em>Given</em><em>, </em><em> </em><em>VXW</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em> </em><em>where</em><em> </em><em>WV</em><em> </em><em>=</em><em>4</em><em> </em><em>and</em><em> </em><em>XV</em><em> </em><em>=</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>b</em><em>y</em><em> </em><em>taking</em><em> </em><em>reference angle</em><em> </em><em>as angle </em><em>W</em><em>,</em><em> </em><em>and</em><em> </em><em>using</em><em> </em><em>tangent</em><em> </em><em>we</em><em> </em><em>get</em><em>;</em>

<em>p</em><em>=</em><em>5</em>

<em>b</em><em>=</em><em>4</em>

<em>again</em><em>, </em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>p</em><em>/</em><em>b</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em> </em><em>5</em><em>/</em><em>4</em>

<em>so</em><em>,</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>1</em><em>.</em><em>2</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>angle</em><em> </em><em>W</em><em>,</em><em> </em><em>we</em><em> </em><em>should</em><em> </em><em>d</em><em>o</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>inverse</em><em>;</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em>-1</em><em>=</em><em> </em><em>tan</em><em> </em><em>thita</em><em>-1</em><em>(</em><em>1</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em> </em><em>-1</em><em> </em><em>=</em><em>5</em><em>1</em><em>.</em><em>3</em><em>4</em><em>0</em><em>1</em><em>°</em><em>.</em>

<em>Now</em><em>,</em><em> </em><em>by</em><em> </em><em>rounding</em><em> </em><em>off</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>(</em><em>angle</em><em> </em><em>W</em><em> </em><em>)</em><em>=</em><em> </em><em>5</em><em>1</em><em>°</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
3 years ago
Can someone please answer this and EXPLAIN how to solve it? ill mark brainliest.
iragen [17]

Answer:

254.34 in^2

Step-by-step explanation:

Replace de values on the formula

a = \pi {r}^{2}  \\ a = (3.14)(9)^{2}  \\ a = 254.34

7 0
2 years ago
Read 2 more answers
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