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PtichkaEL [24]
3 years ago
14

Which of these is an example of pseudoscience?

Chemistry
1 answer:
Nesterboy [21]3 years ago
6 0

Astrology............

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Calculating the pH of a Weak Acid Calculate the pH of a 1 M solution of hydrofluoric acid (HF, K, 7.2 x 101)
kondaur [170]

Answer:

pH = 1.6

Explanation:

  • HF  + H2O ↔ H3O+  +  F-
  • 2H2O ↔ H3O+  +  OH-
  • Ka = ( [ H3O+ ] * [ F- ] ) / [ HF ]

mass balance:

1 M = [ HF ] + [ F- ].........(1)

charge balance:

[ H3O+ ] = [ F- ] + [ OH- ]......[ OH- ] : comes from water, therefore it is negligible.

⇒ [ H3O+ ] = [ F- ]...........(2)

(2) in (1):

1 M = [ HF ] + [ H3O+ ]

⇒ [ HF ] = 1 - [ H3O+ ].........(3)

(2) and (3) in Ka:

⇒ Ka = [ H3O+ ]² / ( 1 - [ H3O+ ] )

∴ Ka = 7.0 E-4.......from literature

⇒ [ H3O+ ]² + 7.0 E-4[ H3O+ ] - 7.0 E-4 = 0

⇒ [ H3O+ ] = 0.0261 M

⇒ pH = 1.6

8 0
4 years ago
Read 2 more answers
Write the chemical equation for the reaction whose enthalpy change is the standard enthalpy of formation of fructose, C6H12O6(s)
ziro4ka [17]

Answer:

6 C(s) + 6_{H2}(g) + 3_{O2}(g)

Explanation:

The chemical equation of the reaction is as follows

According to the question, data provided in the question is shown below:

C_6H_12O_6

The C = Carbon and its standard state is Graphite C(s)

The H = Hydrogen and its standard state is H_2 (s)

The O = Oxygen and its standard state is O_2 (s)

Now the chemical equation for the reaction is

6 C(s) + 6_{H2}(g) + 3_{O2}(g)

5 0
4 years ago
Which coefficient placed before HCl will balance the following<br> equation? Zn+HCI ZnCl2 + H2
cupoosta [38]

Explanation:

Given chemical equation

Zn + HCL ➡ ZnCl2 + H2

Now balancing

Zn + 2HCL ➡ ZnCl2 + H2

Hope it will help :)❤

3 0
3 years ago
What are the three main radioactive elements
DIA [1.3K]
Three main radioactive elements are:

Uranium

Thorium

Radium
6 0
3 years ago
How many grams are in 1.6 moles of potassium bromide?​
slava [35]

Answer:

190.4g

Explanation:

1.6mol of KBr (119.002g KBr/1 mol) = 190.4g

since you want to find grams, take the molar mass of KBr (119.002) per 1 mol and use it as your conversion factor (119.002g KBr/1 mol) which will then cancel out mols and leave you with grams.

6 0
4 years ago
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