Question

Write the chemical equation for the reaction whose enthalpy change is the standard enthalpy of formation of fructose, C6H12O6(s), ΔH∘f[C6H12O6].

Answer 1

Answer:

$6 C(s) + 6_{H2}(g) + 3_{O2}(g)$

Explanation:

The chemical equation of the reaction is as follows

According to the question, data provided in the question is shown below:

$C_6H_12O_6$

The C = Carbon and its standard state is Graphite C(s)

The H = Hydrogen and its standard state is $H_2$ (s)

The O = Oxygen and its standard state is $O_2$ (s)

Now the chemical equation for the reaction is

$6 C(s) + 6_{H2}(g) + 3_{O2}(g)$