When the acid is hydrolyzed, the reaction is
HA --> H⁺ + A⁻
So,
Ka = [H⁺][A⁻]/[HA]
Apply the ICE approach:
HA --> H⁺ + A⁻
I 0.3 0 0
C -X +X +X
E 0.3-X X X
Ka = [X][X]/[0.3-X]
X = H⁺ = A⁻
The formula for pH is:
pH = -log[X]
5.2 = -log[X]
Solving for X,
X = 6.31*10⁻⁶
Therefore,
Ka = [6.31*10⁻⁶][6.31*10⁻⁶]/[0.3-6.31*10⁻⁶]
<span>Ka = 1.33×10⁻¹⁰</span>
corrected question:
A chemist determined by measurements that 0.03 moles of calcium sulfide participate in a chemical reaction. Calculate the mass of calcium sulfide that participates
Answer:
Explanation:
number of moles of CaS
molar mass of CaS = 40+32 = 72g/mol
number of moles = mass/ molar mass
mass = number of moles * molar mass
mass = 0.03 *72
mass of calcium sulfide = 2.16g
The density of PETE is 1.38 g/cm3.
Answer :
The complete equation for the reaction of sulfuric acid and sugar is,
By the stoichiometry of the reaction,
1 mole of sucrose react with the 11 moles of sulfuric acid to give 12 moles of carbon and 11 moles of water.
In this reaction, sulfuric acid react with sucrose (sugar). It dehydrates the sugar molecules which means it eliminates the water.
Answer:
There are 6.022×1023 molecules in a mole. There are 18.01528 grams of water per mole of water. in 1g water
Explanation:
please Mark my answer in brainlist
