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coldgirl [10]
3 years ago
13

AREA ADDITION AND SUBTRACTION URGENT?

Mathematics
2 answers:
qaws [65]3 years ago
6 0

Okay, so we know that the radius of the circle is 7.53

The area of the circle is 178.13, so we'll remember that.

Because the diameter is 15.06, we actually realize that the square is now two triangles, with the hypotenuse being 15.06.

a^2 + b^2 = 15.06^2

Now, because a^2 and b^2 are of the same value, we can basically turn it into this:

2a^2 = 226.8036

a^2 = 113.4018

Doing this actually solves for the square's area:

178.13 - 113.4018 = 64.7282

The yellow region is 64.7282 cm^2

Aleksandr [31]3 years ago
4 0

The area of a circle:

A_C=\pi r^2\\\\r=7.53\ cm\\\\A_C=\pi\cdot(7.53)^2=56.7009\pi\ cm^2\approx56.7009\cdot3.14\approx178.04\ cm^2

The area of a square (like an area of a rhombus):

A_S=\dfrac{d\cdot d}{2}=\dfrac{d^2}{2}\\\\d=2\cdot7.53=15.06\ cm\\\\A_S=\dfrac{15.06)^2}{2}=\dfrac{226.8036}{2}=113.4018\ cm^2\approx113.40\ cm^2

The area of the yellow region:

A=A_O-A_S\\\\A=178.04-113.40=64.64\ cm^2\approx64.6\ cm^2

Answer: 64.4 cm²

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A chord is 10cm from the centre of a circle of radius 15cm. Find the length of the chord.
almond37 [142]

Answer: 21.44 cm

Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

From the figure, the length of the chord is AC

Applying Pythagoras

\Rightarrow AO^2=OB^2+AB^2\\\Rightarrow AB^2=15^2-10^2\\\Rightarrow AB^2=225-100=115\\\Rightarrow AB=\sqrt{115}=10.72\ cm

The length of the chord is AC=2AB=21.44\ cm

5 0
3 years ago
Match the integrals with the type of coordinates which make them the easiest to do.
WARRIOR [948]

Answer:

1. C. cylindrical coordinates

2 A. spherical coordinates

3. A. spherical coordinates

4. D. Cartesian coordinates

5  B. polar coordinates

Step-by-step explanation:

USE THE BOUNDARY INTERVALS TO IDENTIFY

1. ∭E dV where E is:  

x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0  -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0

2. ∭E z^2 dV where E is:  

-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES

3. ∭E z dV where E is:

1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES

4. ∫10∫y^20 1/x dx  ---- This is A CARTESIAN COORDINATES

5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4  This is A POLAR COORDINATES

6 0
3 years ago
A bag is filled with green and blue marbles. There are 125 marbles in the bag. If there are 29 more green
ValentinkaMS [17]

Answer:

89 green marbles and 46 blue marbles

Step-by-step explanation:

3 0
3 years ago
You just purchased two coins at a price of $670 each. Because one of the coins is more collectible, you believe that its value w
DerKrebs [107]

Answer:

The value of first coin will be $151.51 more than second coin in 15 years.

Step-by-step explanation:

You have just purchased two coins at a price of $670 each.

You believe that first coin's value will increase at a rate of 7.1% and second coin's value 6.5% per year.

We have to calculate the first coin's value after 15 years by using the formula

A=P(1+\frac{r}{100})^{n}

Where A = Future value

           P = Present value

           r = rate of interest

           n = time in years

Now we put the values

A=670(1+\frac{7.1}{100})^{15}

A=670(1+0.071)^{15}

A=670(1.071)^{15}

A = (670)(2.797964)

A = 1874.635622 ≈ $1874.64

Now we will calculate the value of second coin.

A=670(1+\frac{6.5}{100})^{15}

A=670(1+0.6.5)^{15}

A=670(1.065)^{15}

A = 670 × 2.571841

A = $1723.13

The difference of the value after 15 years = 1874.64 - 1723.13 = $151.51

The value of first coin will be $151.51 more than second coin in 15 years.

8 0
3 years ago
Identify the linear equation.
slamgirl [31]
I would go with D, it looks like it is the most linear out of the rest, Hope it helps:)
7 0
3 years ago
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