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Answer:
no
Explanation:
its made of a living organisim which in this case is oats
The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
To know more about transmittance click here:
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Answer:
Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.
Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%
Explanation:
Hello,
The Punnett square for this cross turns into:
![\left[\begin{array}{ccc}&G&g\\G&GG&Gg\\G&GG&Gg\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26G%26g%5C%5CG%26GG%26Gg%5C%5CG%26GG%26Gg%5Cend%7Barray%7D%5Cright%5D)
It means that the genotypes and phenotypes are:
Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.
Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%
Best regards.
Answer:
1. Delete lion, bison, reindeer, and giraffe
2. Delete cactus, oak, evergreen,
Explanation:
1. Lions live in the African savanna, bison live in open fields with lots of grass, reindeer live in Antarctica and other very cold places, and giraffes also live in the areas of the African savanna where there are trees.
2. Cacti live in the desert, oaks and evergreens live in open grassy areas.
Hope this helps
