A golfer starts with the club over her head and swings it to reach maximum speed as it contacts the ball. Halfway through her sw
ing, when the golf club is parallel to the ground, does the acceleration vector of the club head point straight down, parallel to the ground, approximately toward the golfer's shoulders, approximately toward the golfer's feet, or toward a point above the golfer's head?
A. Parallel to the ground, approximately toward the golfer's shouldersB. Straight downC. Approximately toward the golfer's feetD. Toward a point above the golfer's head
A. Parallel to the ground, approximately toward the golfer's shouldersB. Straight downC. Approximately toward the golfer's feetD. Toward a point above the golfer's head
1 answer:
Answer:
A. Parallel to the ground, approximately toward the golfer's shoulders
Explanation:
Elliptical path represent the motion of the golf club.
From the figure we have the motion of the club. So the acceleration provided will be centripetal acceleration so halfway through the swing the direction of acceleration will be towards the golfer's shoulder.
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Answer:
The escape velocity on the planet is approximately 178.976 km/s
Explanation:
The escape velocity for Earth is therefore given as follows
The formula for escape velocity, , for the planet is
Where;
= The escape velocity on the planet
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m = The mass of the planet = 12 × The mass of Earth,
r = The radius of the planet = 3 × The radius of Earth,
The escape velocity for Earth, , is therefore given as follows;
= 16 ×
Given that the escape velocity for Earth, ≈ 11,186 m/s, we have;
The escape velocity on the planet = ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.