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Elden [556K]
3 years ago
9

The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm(red) and 486 nm (blue). Light fr

om a hydrogen lamp illuminates a diffraction grating with 520lines/mm , and the light is observed on a screen 1.5m behind the grating.
What is the distance between the first-order red and blue fringes?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

0.152 m

Explanation:

The condition for constructive interference is

d sinθ= mλ  (m= 0,1,2,3...)

the slit width

d= 1/N

d= 10^(-3)/520

= 1.92×10^(-6)

The angular spread for the red light is

\theta_r= sin^{-1}(\frac{m\lambda}{d})

\theta_r= sin^{-1}(\frac{656\times10^{-9}}{1.92\times10^{-6}})

= 19.97°

The angular spread of blue light is

\theta_b= sin^{-1}(\frac{m\lambda}{d})

\theta_b= sin^{-1}(\frac{456\times10^{-9}}{1.92\times10^{-6}})

=14.66°

The distance between the first order red fringe and blue fringe is,

y= y_r- y_b = Ltanθ_r -Ltanθ_b

=1.50( tan19.97°-tan14.66°) = 0.152 m

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A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

\Delta p=m\Delta v=m(v_2-v_1)

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

\Delta p=F.\Delta t

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

\Delta p=14*0.06=0.84

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A drone is flying horizontally when it runs out of battery and begins to free fall from 20m. No drag. If it lands 60m away (in t
rewona [7]

Answer:

Explanation:

Remark

At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.

Givens

h = 20 m

hd = 60 m

g = 9.81

vi = 0

Formula

d = vi*t + 1/2 a * t^2                  We are solving for t

Solution

When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters

d = 0*t + 1/2 * 9.81 a* t^2

20 = 4.91 * t^2                          Divide by 4.91

20/4.91 = 4.91 t^2 / 4.91    

4.073 = t^2                              Take the square root of both sides.

t = 2.02 seconds

Horizontal

d = 60 m

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v = ?

Note: there is no horizontal deceleration or acceleration

v = d/t

v = 60/2.02

Answer: v = 29.73 m/s

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2 years ago
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