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3 years ago

What occurs when two Stars collide into each other?

Physics

2 answers:

ddd [48]3 years ago

5 0

Answer:

A stellar collision.

Explanation:

A stellar collision is the coming together of two stars caused by stellar dynamics within a star cluster, or by the orbital decay of a binary star due to stellar mass loss or gravitational radiation, or by other mechanisms not yet well understood.

mash [69]3 years ago

4 0

Answer:

they either form a black hole or merge into a larger star

Explanation:

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The tools to distinguish the thickness of two objects of thickness of 1.92mm and the other with thickness of 1.93mm is ?

melomori [17]

Answer:

the instrument that gives this precision is the micrometer screw

Explanation:

The high precision measurements of small parts are the general vernier and the micrometer screw.

In these two instruments the same principle is used: there is a fixed rule and a mobile one that increases precision.

Let's analyze the absolute error or precision of each instrument

* For the vernier, the precision of the fixed rule is 1 mm and there are 20 divisions (the most common); therefore the precision of the instrument is

Δx = 1 mm / 20

Δx = 0.05 mm

* For the micrometer screw, the precision of the fida rule is 0.5 mm and the number of divisions is 50, therefore the precision of the screw is

Δx = 0.5mm / 50

Δx = 0.01 mm

consequently the instrument that gives this precision is the micrometer screw

8 0

3 years ago

A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de

oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

$\eta = \frac{W}{Q_{in}}$

where

W is the useful work done by the engine

$Q_{in}$ is the heat in input to the machine

In this problem, we have:

$Q_{in}=600 kJ$ is the heat absorbed

$W=600 kJ-175 kJ=425 kJ$ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

$\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%$

(a) $737^{\circ}C$

The efficiency of an engine can also be rewritten as

$\eta = 1-\frac{T_C}{T_H}$

where

$T_C$ is the absolute temperature of the cold sink

$T_H$ is the temperature of the source

In this problem, the temperature of the sink is

$T_C = 20^{\circ}C + 273=293 K$

So we can re-arrange the equation to find the temperature of the source:

$T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C$

7 0

3 years ago

15 points

Marizza181 [45]

Basaltic magma is the A. The least explosive type of magma.

6 0

3 years ago

Object A has 25 J of kinetic energy. Object B has one-quarter the mass of object A.By what factor does the speed of each object

Natalka [10]

Answer:

The speed of object B is 2 times of speed of object A.

Explanation:

Given that,

Kinetic energy of object A = 25 J

Mass of object B $m_{B}=\dfrac{1}{4}m_{A}$

Work done = -20 J

We need to calculate the factor of the speed of the object

Suppose the final kinetic energy is same for both object.

$K.E_{f_{A}}=K.E_{f_{B}}$

$\dfrac{1}{2}m_{A}v_{A}^2=\dfrac{1}{2}m_{B}v_{B}^2$

Put the value into the formula

$\dfrac{1}{2}m_{A}\times v_{A}^2=\dfrac{1}{2}\times\dfrac{1}{4}m_{A}\times v_{B}^2$

$\dfrac{v_{A}}{v_{B}}=\dfrac{1}{2}$

$v_{A}=\dfrac{1}{2}v_{B}$

$v_{B}=2v_{A}$

Hence, The speed of object B is 2 times of speed of object A.

4 0

3 years ago

Read 2 more answers

II. Magnetic fields Magnets and magnetic fields EM 115 We have observed that magnets interact even when they are not in direct c

nasty-shy [4]

Solution :

We all know that a bar magnet have two poles, the north pole and the south pole. These poles interacts with each other. The ends of the magnets having similar poles will push each other away while the poles with like charges will pull each others towards it.

The compass needle is also a magnet having south polarity as well as north polarity. When the compass needle is close to the bar magnet, it is opposite to the poles or along the poles. The compass needle shows the direction or is pointed towards the north. So when the compass needle is placed near the north pole of the bar magnet, the pointer of the compass needle points towards the north, i.e. it gets deflected because of he like charges. And when it is placed near the south pole of the magnet, it gets attracted towards it and is pointed towards the pole.

Now as we move the compass needle from the poles to the region that is between the poles, the compass needle pointer points towards the north direction every time. It show a deflection always. If we place the magnetic lines, we will see that the magnetic lines will exit from the north poles and enters the south pole of the bar magnet.

3 0

3 years ago