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Crazy boy [7]
3 years ago
7

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

are both traveling at the same speed of 23.0 m/s , and the distance between them is 53.0 m . After t1 = 4.00 s , the motorcycle starts to accelerate at a rate of 7.00 m/s2 . The motorcycle catches up with the car at some time t2.
Physics
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

t₂ = 3.89 s

Explanation:

given,

speed of car  = 23 m/s

speed of motorcycle = 23 m/s

after time of 4 s distance between them is equal to = 53 m

motorcycle accelerates at = 7 m/s

time taken to catch up with car = ?

let t₂ be the time in which motorcycle catches car.

distance traveled by car in t₂ s

d = 23 t₂ + 53

distance traveled by motorcycle

using equation of motion

s = ut + \dfrac{1}{2}at^2

s = 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

now, equating both the distances

23t_2 + 53= 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

t_2^2 = 15.143

    t₂ = 3.89 s

time taken by the motorcycle to catch the car is equal to 3.89 s

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Refer to the diagram shown.

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6 0
2 years ago
Camille knows that range of motion is very important. She is designing a weekly exercise program and is not sure where flexibili
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Any ss2 here (11th Grade)
Sever21 [200]

Answer:

<h2>a) 50°</h2><h2>b) 40°</h2>

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Check the complete diagram n the attachment below

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