Foraging bees often move in straight lines away from and toward their hives. Suppose a bee starts at its hive and flies 500 m du
1 answer:
Answer:
The distance of the bee from the hive is 740 m.
Explanation:
Given that,
Bee starts fly 500 m due east, 430 m west and 670 m east.
The direction of the bee
500 m in positive direction
430 m in negative direction
670 m in positive direction
We need to calculate the net distance
Using formula of distance
Hence, The distance of the bee from the hive is 740 m.
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Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required:
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
Answer:
1.45544 J
Explanation:
See attachment
Answer:
a= - 6.667 m/s²
Explanation:
Given that
The initial speed of the box ,u= 20 m/s
The final speed of the box ,v= 0 m/s
The distance cover by box ,s= 30 m
Lets take the acceleration of the box = a
We know that
v²= u ² + 2 a s
Now by putting the values in the above equation we get
0²=20² + 2 a x 30
a= - 6.667 m/s²
Negative sign indicates that velocity and acceleration are in opposite direction.
Therefore the acceleration of the box will be - 6.667 m/s² .