4. According to Newton third law what is the action force? The swimmer pushes against the water the water pushes back on the swi
mmer and pushes he forward
A. The swimmer pushing against the water
B. The water pushing on the swimmer
C. The friction as the swimmer dives into the water
D. The mass of the water
5. According to Newton’s third law what is the reaction force? The ball put a force on the wall, and the wall puts a force on the ball bounces off
A. The balls force against the wall
B. The ball inertia
C. The walls force against the ball
D. The walls mass
PLEASE ANSWER ALL
PLEASE ANSWER ALL CORRECT!!!!!
A. The swimmer pushing against the water
B. The water pushing on the swimmer
C. The friction as the swimmer dives into the water
D. The mass of the water
5. According to Newton’s third law what is the reaction force? The ball put a force on the wall, and the wall puts a force on the ball bounces off
A. The balls force against the wall
B. The ball inertia
C. The walls force against the ball
D. The walls mass
PLEASE ANSWER ALL
PLEASE ANSWER ALL CORRECT!!!!!
2 answers:
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Answer:
c)
Explanation:
Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:
where k is a proportionality constant with the value
In this case , so we have:
Solving the equation for q, we have:
Replacing the given values:
Answer:
a) 200A
b) 10.2V
c) 2.04kW
d)
I=80A
V=4.08V
P=0.326kW
Explanation:
Here we have a circuit of one power source and two resistors in series, the first question is asking for the current, so according to Ohm's Law:
Where R is the equivalent resistance of the resistors in series
To calculate the voltage dropped by the motor we have to apply the voltage divider rule:
The power dissipated supplied to the motor is given by:
now solving adding a 0.0900 ohm resistor:
Answer:
D) the second at the doorknob
Explanation:
The torque exerted by a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation
is the angle between the direction of the force and d
In this problem, we have:
- Two forces of equal magnitude F
- Both forces are perpendicular to the door, so
- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force
--> therefore, the 2nd force exerts a greater torque