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4 years ago

How are velocity and displacement related?

1 answer:

7 0

Velocity is the rate at which displacement changes with time. It is a vector, too. The average velocity over some interval is the total displacement during that interval, divided by the time. ... Speed is a scalar, which describes the total distance travelled by some object during some time interval. Plze mark me brainiest

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A ski resort consists of a few chairlifts and several interconnected downhill runs on the side of a mountain, with a lodge at th

Aleks04 [339]

A sketch of the junction between one chairlift and two runs is shown in the image attached below.
For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

<h3>What is Kirchhoff's loop rule?</h3>

Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.

<h3>How to connect two runs in series?</h3>

Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.

For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

Read more on Kirchhoff's loop rule here: brainly.com/question/15003023

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7 0

2 years ago

A stone is thrown vertically upward with a speed of 18 m/s. (a) How long does it take the stone to reach a height of 11 m? (b) h

bagirrra123 [75]

Answer:

a) It takes the stone 0.7743 s to reach a height of 11 m for the first time on its way up and 2.899 s to reach again that height on its way down.

b) At t = 0.7743 s the velocity is 10.41 m/s and at t = 2.899 s the velocity is -10.41 m/s.

c) There are two answers because the stone reaches the height of 11 m one time on its way up and one more time again on its way down.

Please, see the attached figures and the explanation for a description of the figures.

Explanation:

Hi there!

The equations for the height and velocity of the stone are as follows:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height

y0 = initial height

v0 = initial velocity

t = time

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive)

v = velocity at time t

a) Let´s calculate the time it takes the stone to reach a height of 11 m. The origin of the frame of reference is at the throwing point so that y0 = 0:

y = y0 + v0 · t + 1/2 · g · t²

11 m = 18 m/s · t - 1/2 · 9.8 m/s² · t²

0 = -4.9 m/s² · t² + 18 m/s · t - 11 m

Solving the quadratic equation:

t = 0.7743 s and t = 2.899 s

(Notice that I have used more significant figures to avoid error by rounding)

The stone will be two times at a height of 11 m, one on its way up (at 0.7743 s) and one on its way down (at 2.899 s). Then, it takes the stone 0.7743 s to reach a height of 11 m for the first time.

b) Let´s use the equation of velocity:

v = v0 + g · t

at t = 0.77443 s

v = 18 m/s - 9.8 m/s² · 0.77443 s

v = 10.41 m/s

at t = 2.899 s

v = 18 m/s - 9.8 m/s² · 2.899 s

v = - 10.41 m/s

(Both velocities have to be of the same magnitude but of different sign, that´s why I haven´t rounded the time.)

c) There are two answers because the stone reaches the height of 11 m one time on its way up and one more time again on its way down. On its way up, the velocity is 10.41 m/s and on its way down it is -10.41 m/s.

Figures

The functions to plot are the following:

height in function of time (figure 1, x-axis: time. y-axis: height)

y = -4.9t² + 18t

velocity in function of time (figure 2, x-axis: time. y-axis velocity)

v = -9.8t + 18

Acceleration in function of time (figure 3, x-axis: time. y-axis: acceleration)

a = -9.8

5 0

4 years ago

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.

Aleksandr [31]

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3?

a. it is reduced by a factor of 3

4 0

3 years ago

Formulating an Investigative Question

valentina_108 [34]

Answer:

How do mass and speed affect kinetic energy?

Explanation:

This was edges sample resopnse so do not copy and just put this in your own words.

Have a great day whoever reads this.

8 0

3 years ago

The Moon has a mass of 7.35 * 1022 kg, and a radius of 1.737 * 106 m. Based on

suter [353]

Answer:

1.63 $ms^{-2}$

Explanation:

The equation $g = \frac{G*M}{R^2}$ would be used where:

g = acceleration due to gravity

G = universal gravitational constant (6.67408 × $10^{-11}$ $m^{3} kg^{-1} s^{-2}$ )

M = mass

R = radius.

assuming the values following both 10s of the mass and radius are their exponents, which is a little confusing, the values given would simply be substituted.

Anyone can correct me if I'm wrong.

7 0

3 years ago