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deff fn [24]
3 years ago
6

How are velocity and displacement related?

Physics
1 answer:
Keith_Richards [23]3 years ago
7 0

Velocity is the rate at which displacement changes with time. It is a vector, too. The average velocity over some interval is the total displacement during that interval, divided by the time. ... Speed is a scalar, which describes the total distance travelled by some object during some time interval. Plze mark me brainiest

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Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell
NARA [144]

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

5 0
3 years ago
0.22 L of pancake syrup has a mass of 33 g.
katrin2010 [14]

Answer:

a. 150 g/L

b. 75 g

c. 120 mL

Explanation:

a. 33g/0.22L=150 g/L

b. 33g/0.22L=150 g/L

150 g/L*0.5L=75g

c. 0.22L/33g=0.006667L/g

0.006667L/g*18g=0.12L

0.12L*1000=120mL

6 0
3 years ago
The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit
Margaret [11]

Let  us consider two bodies having masses m and m' respectively.

Let they are  separated by a distance of r from each other.

As per the Newtons law of gravitation ,the gravitational force between two bodies is given as -  F = G\frac{mm'}{r^{2} }   where G is the gravitational force constant.

From the above we see that F ∝ mm' and F\alpha \frac{1}{r^{2} }

Let the orbital radius of planet  A is r_{1}  = r and mass of planet is m_{1}.

Let the mass of central star is m .

Hence the gravitational force for planet A  is f_{1} =G \frac{m_{1}*m }{r^{2} }

For planet B the orbital radius  r_{2} =2r_{1} and mass m_{2} = 3 m_{1}

Hence the gravitational force f_{2} =G\frac{m m_{2} }{r^{2} }

                                                 f_{2} =G\frac{m*3m_{1} }{[2r_{1}] ^{2} }

                                                 = \frac{3}{4} G\frac{mm_{1} }{r_{1} ^{2} }

Hence the ratio is  \frac{f_{2} }{f_{1} } = \frac{\frac{3}{4}G mm_{1/r_{1} ^2}  }{Gmm_{1}/r_{1} ^2 }

                                      =\frac{3}{4}     [ ans]


                                                 

                           

3 0
3 years ago
Read 2 more answers
A circuit is made of a battery, a light bulb, and a 2 resistor. The battery has a voltage of 3 volts. When connected, the ammete
Monica [59]

Answer:

3ohms

Explanation:

From Ohm's Law

V = IR

V is that voltage = 3volts

I = current = 1amp

R = resistance in ohms

Putting those values into the above formula.

3volts = 1amp×R

Making R the subject

R = 3/1

R = 3ohms

The resistance of the light bulb is 3ohms.

6 0
3 years ago
Energy Calculation 4. What is the gravitational potential energy of an object that has a mass of 100kg it is 10m off of the grou
konstantin123 [22]
100kg * 9.8N/kg * 10m = 9800

3 0
2 years ago
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