The concept of Archimedes' principle is that an object immersed in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. The fluid displaced has a weight W = mg, where g is acceleration due to gravity. Therefore, the weight of the displaced fluid can be expressed as W = ρVg.
Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
So what's the question here?
<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>
Given that ,
- Initial Velocity of car = 44km / hr.
- Final Velocity of car = 0km / hr.
- Acceleration = -5km/hr².
To Find :
- Time taken to stop the car .
So , here use first equⁿ of motion which is ,
where ,
- v is final Velocity.
- u is Initial velocity.
- a is acceleration.
- t is time taken.
Now , substituting the respective values ,
