Question

John is building a fence for the animals on his farm. The perimeter of the rectangle should be less than 100 meters. The length of the rectangle is 4 meters more than the width. Which inequality expresses all of the possible widths, in meters, of the rectangle?

Answer 1

Answer:

$w$

Step-by-step explanation:

Let l be the length and w be the width of the rectangle

Given:

The length of the rectangle is 4 meters more than the width.

The length of the rectangle is

$l = 4 + width = 4+w$

The perimeter of the rectangle should be less than 100 meters.

The perimeter of the rectangle is $2(l+w)$ and it is less than 100 m.

So, the equation is.

$2(l+w)$

Put length of the rectangle in above equation.

$2((4+w)+w)$

$2(4+2w)$

$8+4w$

$4w$

$4w$

$w$

$w$

Therefore, the inequality expresses all of the possible widths is $w$