Q=mc(delta T)
m= Q/ c(delta T)
m= 1200 J / (4.19 J/kg C) (15-10)
m= 57. 28 kg
Answer :
YES, The precipitation reaction will occur.
Explanation : When we mix the aqueous solutions of Lead chloride and Ammonium sulfide a reaction will occur which is stated below :
![PbCl_{2} +(NH_{4}) _{2} S ----\ \textgreater \ PbS + 2[ (NH_{4})Cl]](https://tex.z-dn.net/?f=PbCl_%7B2%7D%20%2B%28NH_%7B4%7D%29%20_%7B2%7D%20S%20----%5C%20%5Ctextgreater%20%5C%20%20PbS%20%2B%202%5B%20%28NH_%7B4%7D%29Cl%5D%20)
The major product that is formed is Lead sulfate which is black in colour.
Once the reaction is complete one can observe a black precipitate getting obtained.
An electron is found whizzing around the nucleus, so in subatomic particles.
Endothermic reaction is the answer.
Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of
.
Explanation:
To calculate the moles :

The balanced chemical equation for decomposition of
is:
According to stoichiometry :
2 moles of
give = 2 moles of 
Thus 0.113 moles of
give =
of 
Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of
.