The charge of a nucleus is neutral, meaning it’s zero
the positive charges of an atom equal the negative charges so the atom has a neutral charge
Answer:
Option A.
Explanation:
1 mol of anything contains 6.02×10²³ particles.
We know that 1 mol of oxygen gas contains 2 moles of O.
1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.
By the way, the mass for 1 mol of O₂ may be:
Option A → 16 g/mol . 2 mol
32 g
Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.
Another example can be:
1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.
The question is incomplete, the complete question is;
1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?
A. CL2
B. SF6
C. Kr
D. UF6
E. Xe
Answer:
SF6
Explanation:
From Graham's law;
Let the rate of diffusion of oxygen be R1
Let the rate of diffusion of unknown base be R2
Let the molar mass of oxygen by M1
Let the molar mass of unknown gas be M2
Hence;
R1/R2 = √M2/M1
So;
2.14/1 = √M2/32
(2.14/1)^2 = M/32
M= (2.14/1)^2 × 32
M= 146.6
This is the molar mass of SF6 hence the answer above.
Answer: option (a) is the correct answer
Explanation:
The complete questions says;
You observe an exothermic gaseous reaction that is not spontaneous in forward direction at 1 atm and 298K. Which of the following statements about this reaction is true? a. This reaction will become spontaneous in forward direction at some temperature below 298K. b. This reaction will be spontaneous in forward direction at a higher pressure at 298K. c. This reaction will become spontaneous in forward direction at some temperature above 298K. d. This reaction is never spontaneous. e. The reverse reaction is always spontaneous.
The Answer:
(a). This reaction will become spontaneous in forward direction at some temperature below 298K
Explanation: First of all, we can acknowledge that the reaction seen here is an exothermic one, i.e energy is released in the process outwardly and as a result temperature is reduced during this process of energy loss.
Having understood that scenario, say we reduce it's temperature by ourself than forward reaction favors and after reaching at particular temperature, therefore we can confirm this to be a spontaneous reaction.
Let us use this to confirm what we have been saying.
Given;
ΔG = ΔH - TΔS
here ΔH is negative
it is non spontaneous, which means ΔG is positive so we continuously decraeses it's temperature than at a particular temperature.
The Entropy change becomes positive and reaction becomes spontaneous and ΔG become negative.
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