A line parallel to x-axis has 0 slope.
1/6 of an hour is 10 minutes. For a precise answer, convert it to seconds. You will end up with 600 seconds. Divide the area of the sheet by 600 seconds.
1260/600 ~ 2
With this result, Samantha glued approximately 2 stickers every second.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
To learn more on cubic polynomials: brainly.com/question/21691794
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34 square feet
Explanation:
Cut the shape into two shapes. The bottom will be a square and the top will be a long rectangle.
The area of the rectangle is 18 square feet
(Multiply 9 x 2)
The area of the square is 16 square feet
(Multiply 4 x4)
18 + 16 = 34
MARK BRAINLIESTT
Please! And thank u, trust me, this is the answer
The first thing you should do for this case is to use the following table to perform the equation of a line:
y x
41,431 1995
48,729 2005
We have then that the line that best fits this data is
y = 729.8x - 1E + 06
Then, to know in what year the number of shopping centers reaches 80,000 we must replace this number in the equation of the line and clear x:
80000 = 729.8x - 1E + 06
Clearing x
x = (80000 + 1E + 06) / (729.8) = 1479.857495
nearest whole number
1480
This means that after 1480 years, 80000 shopping centers are reached.
Equivalently, this amount is reached in the year:
1480 + 1995 = 3475
In the year 3475
answer
(a) y = 729.8x - 1E + 06
(b) In the year 3475
