What would we see if we were able to travel within the multiverse?

Dalila plans an experiment to examine plant growth. She

Hoochie [10]

Answer:

The answer is: a column that shows how the dependent variable changes.

Explanation:

An experiment is a process that is carried out by a researcher in order to find out whether his hypothesis is valid. In order to conduct a proper experiment, it is very important to include both the "dependent" and "independent" variables.

A dependent variable refers to the variable that changes in response to the presence of an independent variable. On the contrary, an independent variable is the variable (such as factors) that is being changed in order to control the experiment.

Remember that independent variables do not depend on other factors. Thus, it is only the dependent variable's change that matters in an experiment.

This is the reason why Dalila needs to have a column that shows the dependent variable changes (and not the independent variable changes).

4 0

3 years ago

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Solve the science problem

scZoUnD [109]

Answer:

What is the problem I cant help unless you have the problem.

Explanation:

5 0

3 years ago

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As demonstrated by the Doppler Effect, why does sound increase in pitch as a sound source approaches you?

scZoUnD [109]

I think so it ans wold be d.because if the source approaches the observer more and more wavefront will pass and it get squeezed.so wavelength decreases and frequency increases.

3 0

3 years ago

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The equation that is used to solve second law problems is # F= ma.

maw [93]

F= Force
M=Mass
A= acceleration
F=N
Mass= in grams or kilo grams (mostly kg)
A= m/s

8 0

3 years ago

A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr

rjkz [21]

Answer:

Part A

I = 1.4 mW/m²

Part B

β = 91.46 dB

Explanation:

Part A

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

$I = \frac{P}{A}$

$I = \frac{P}{4\pi r^{2}}$

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

$I = \frac{34}{4\pi (44)^{2}}$

I = 0.0013975 W/m²

≈ I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

Part B

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value. It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;

β $= 10log_{10}\frac{I}{I_{0}}$ dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

∴ β $= 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}$

β $= 10log_{10} (1.4 * 10^{9})$

β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.

4 0

3 years ago